grep/egrep end of pattern

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# 1  
grep/egrep end of pattern


I use arp to get the mac-addresses of my hosts.

 # arp -a | grep 192.168.0.
e1000g0   o        00:00:00:00:00:01
e1000g0 o        00:00:00:00:00:02
e1000g0            00:00:00:00:00:03
e1000g0 o        00:00:00:00:00:04
e1000g0            00:00:00:00:00:05
e1000g0           00:00:00:00:00:06

How can I grep/egrep for just one host? I'd like to have the following:

 # arp -a | grep ""
e1000g0   o        00:00:00:00:00:01

and not

  # arp -a | grep ""
 e1000g0   o        00:00:00:00:00:01
 e1000g0 o        00:00:00:00:00:02

# 2  
Try the -w option of grep.

# 3  
Thanks. Exactly what I need.
Sorry for my stupid question Smilie
# 4  
you can also try out as
arp -a | grep " "
# 5  
Originally Posted by pradeepreddy
you can also try out as
arp -a | grep " "
Why should you use a workaround if there's an option for?

# 6  
Why should you use a workaround if there's an option for?
My words Smilie

But I have an other question:

How can I grep/egrep for exactly two (192.168.1 AND 192.168.2 for example) hosts?

arp -a | egrep '192.168.0.(1|2)'

This egrep delivers four hosts.

Last edited by domi55; 05-12-2009 at 10:27 AM..
# 7  
arp -a | awk '{print $2}' | grep "192.168.0.[1-2]$"

check this out
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