grep/egrep end of pattern


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# 1  
grep/egrep end of pattern

Hi

I use arp to get the mac-addresses of my hosts.

Code:
 # arp -a | grep 192.168.0.
e1000g0   192.168.0.1            255.255.255.255 o        00:00:00:00:00:01
e1000g0   192.168.0.11          255.255.255.255 o        00:00:00:00:00:02
e1000g0   192.168.0.2            255.255.255.255          00:00:00:00:00:03
e1000g0   192.168.0.22          255.255.255.255 o        00:00:00:00:00:04
e1000g0   192.168.0.3            255.255.255.255          00:00:00:00:00:05
e1000g0   192.168.0.33            255.255.255.255         00:00:00:00:00:06

How can I grep/egrep for just one host? I'd like to have the following:

Code:
 # arp -a | grep "192.168.0.1"
e1000g0   192.168.0.1            255.255.255.255 o        00:00:00:00:00:01

and not

Code:
  # arp -a | grep "192.168.0.1"
 e1000g0   192.168.0.1            255.255.255.255 o        00:00:00:00:00:01
 e1000g0   192.168.0.11          255.255.255.255 o        00:00:00:00:00:02

# 2  
Try the -w option of grep.

Regards
# 3  
Thanks. Exactly what I need.
Sorry for my stupid question Smilie
# 4  
you can also try out as
arp -a | grep "192.168.0.1 "
# 5  
Quote:
Originally Posted by pradeepreddy
you can also try out as
arp -a | grep "192.168.0.1 "
Why should you use a workaround if there's an option for?

Regards
# 6  
Quote:
Why should you use a workaround if there's an option for?
My words Smilie

But I have an other question:

How can I grep/egrep for exactly two (192.168.1 AND 192.168.2 for example) hosts?

Code:
arp -a | egrep '192.168.0.(1|2)'

This egrep delivers four hosts.

Last edited by domi55; 05-12-2009 at 10:27 AM..
# 7  
arp -a | awk '{print $2}' | grep "192.168.0.[1-2]$"

check this out
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