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Piping and assigning output to a variable in Perl

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# 8  
Old 05-13-2009
Hi,

I got this syntax msg when i do a syntax check.
Can anybody advise me on this error message ?

Code:
$ !!
perl -c testing
Name "main::ST_file" used only once: possible typo at testing line 35.
testing syntax OK

# 9  
Old 05-13-2009
Hi,

I just a simpler code to simulate the unix command, but how am i suppose to assign the string being printed out to a variable ?
Tried to use the below but it can't work.
Can any expert help ?

Code:
open(F, " ls -rt *$tester*st* | tail -1 | ") or die;
while (<F>) {
        my $ST_file = sprintf("%s",$_);
}
print "$ST_file\n";

# 10  
Old 05-13-2009
Hi ,

Through Try and Error , i finally found out the way to do it.
Can any expert explain why with " while ($line=<F>) ", it is able to work ?
But with " while (<F>) " , it is not able to work ?

Correct Code:
Code:
open(F, " ls -rt *$tester*st* | tail -1 | ") or die;
while ($line=<F>) {
        chomp;
        my $ST_file = sprintf("%s",$line);
}
close(F);
print "$ST_file\n";

Wrong Code:
Code:
open(F, " ls -rt *$tester*st* | tail -1 | ") or die;
while (<F>) {
        chomp;
        my $ST_file = sprintf("%s",$_);
}
close(F);
print "$ST_file\n";

# 11  
Old 05-13-2009
You have declared $ST_file in the wrong scope.:


Code:
my $ST_file; 
open(F, " ls -rt *$tester*st* | tail -1 | ") or die;
while (<F>) {
        chomp;
        $ST_file = $_;
}
close(F);
print "$ST_file\n";
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