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How can i passed a parameter to a file?

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# 1  
Old 04-28-2009
How can i passed a parameter to a file?
i got a file called Pass1, and then i need to passed a number to my script with the '-p pass_mark' option.

Example type
Pass1 -p 18

to pass 18 to my script for comparing things, so how can i do it?
# 2  
Old 04-28-2009
If you want named parameters, check up on the getopts function (available in a ksh and bash near you)
If you only want to pass any parameter, they are automagically stored in $1 to $9 individually and $*/$@ collectively.
# 3  
Old 04-28-2009
example:

Code:
whie getopts "p:" opt
do
case $opt in
p) pass_mark = $OPTARG ;;
esac
done

In your cass to pass , just the mark, you could just run the script as
Code:
scriptname 45

and then in your script, accept
Code:
pass_mark=$1


cheers,
Devaraj Takhellambam
shift $((OPTIND -1))
# 4  
Old 04-28-2009
Quote:
Originally Posted by devtakh
example:

Code:
whie getopts "p:" opt
do
case $opt in
p) pass_mark = $OPTARG ;;
esac
done

In your cass to pass , just the mark, you could just run the script as
Code:
scriptname 45

and then in your script, accept
Code:
pass_mark=$1


cheers,
Devaraj Takhellambam
shift $((OPTIND -1))
Thank you
# 5  
Old 04-29-2009
i did somethings like that, but is not working

Code:
while getopts "p:" opt
do
case $opt in
p) pass_mark = $OPTARG ;;
esac
done

pass_mark=$1

if [ 50 -lt $1 ]
then
echo "50 is less than $1"
else
echo "50 is not less than $1"
fi

# 6  
Old 04-29-2009
can i use other command in stead of getopts?
# 7  
Old 04-29-2009
Quote:
Originally Posted by mingming88
can i use other command in stead of getopts?
Yes you could just use a command line parameter.

In your script

Code:
pass=$1
if [ $pass -lt 50 ]; then
echo "Pass mark of $pass is less than 50"
else
echo "Pass mark of $pass is greater than 50"
fi

Run the script as

Code:
scriptname 45

cheers,
Devaraj Takhellambam
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