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Use variable in sed don't work.

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# 1  
Old 04-07-2009
Use variable in sed don't work.

Hi all.

I have a script as below:
cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n "/$cutmth/$p" alert_sbdev1.log > alert_summ.log

My purpose is to run through the alert_sbdev1.log and find the 1st occurence of 'Jan' and send everything after that line to alert_summ.log.

When I execute my script, i get this error:
sed: 0602-403 /Jan/ is not a recognized function.

What is wrong with my script? Please help. Thanks.
# 2  
Old 04-07-2009
Place a comma after the last slash:

sed -n "/$cutmth/,$p" alert_sbdev1.log > alert_summ.log

# 3  
Old 04-07-2009

I amended my script to below, but still got error.

cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n "/$cutmth/,$p" alert_sbdev1.log > alert_summ.log

sed: 0602-404 Function /Jan/, cannot be parsed.

# 4  
Old 04-07-2009
try this
cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n /$cutmth'/,$p' alert_sbdev1.log > alert_summ.log

# 5  
Old 04-08-2009
Hi vidyadhar85,

Thanks! Got it working! =)

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