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NAWK - seach pattern for special characters - } dbl qt - sng qt

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# 1  
Old 04-03-2009
NAWK - seach pattern for special characters - } dbl qt - sng qt
i'm puzzled....

trying to look for the pattern }"'. but the below code returns to me the message below (pattern is curley queue + dbl qt + sng qt + period)

Quote:
awk: 0602-592 String }"'. cannot contain a newline character. The source line is 1.

Code:
  
nawk -v pat="\}\"\'\."'
          {
            if (match($0, pat)) {
               before = substr($0,1,RSTART-1);
                 do {
                     pattern = substr($0,RSTART,RLENGTH);
                     printf("%s%s\n", before, pattern);
                     $0=substr($0, RSTART+RLENGTH)
                    } while (match($0, pat))
                 }
          }' $HOME/TEMP/X1.dat >> $HOME/TEMP/X2.dat

Quote:
Thank you in advance for your help!
# 2  
Old 04-03-2009
a sample data file, please.
# 3  
Old 04-03-2009
I'm sure its not this easy, but is it a direct cut and paste of your code?

Code:
  
nawk -v pat="\}\"\'\."'

It looks like the last single quote is out of place...

Code:
nawk -v pat="\}\"\'\."

# 4  
Old 04-03-2009
sample data file:

Quote:

mp itable Join_plcy_trm_plcy_sts_prty_Extract__table_ "$SCHEMA_DB"'/db2eee_cr.dbc' -select 'WITH S_PH AS (SELECT PLCY_KY,
Max(s.PLCY_EVNT_KY) as PLCY_EVNT_KY
FROM '"${Gedwschema}"'.plcy_sts s, '"${Gedwschema}"'.vhcl v
output to be 2 results

1rst result for "${Gedwschema}"'.plcy_sts
2nd result for '"${Gedwschema}"'.vhcl
# 5  
Old 04-03-2009
The output is different though...
Code:
nawk -v pat="}\"'\." -f dan1.awk dan1.txt

# 6  
Old 04-03-2009
Quote:
Originally Posted by d.f.
I'm sure its not this easy, but is it a direct cut and paste of your code?

Code:
  
nawk -v pat="\}\"\'\."'

It looks like the last single quote is out of place...

Code:
nawk -v pat="\}\"\'\."


the single quote you removed at the end of the nawk line (i think ??) encapsulates the whole rest of the expression... no?


Code:
 
nawk -v pat="\}\"\'\."'
          {
            if (match($0, pat)) {
               before = substr($0,1,RSTART-1);
                 do {
                     pattern = substr($0,RSTART,RLENGTH);
                     printf("%s%s\n", before, pattern);
                     $0=substr($0, RSTART+RLENGTH)
                    } while (match($0, pat))
                 }
          }' $HOME/TEMP/X1.dat >> $HOME/TEMP/X2.dat

# 7  
Old 04-03-2009
My bad.....
needed a space before the single quote that incapsulates all that comes after the nawk line..... i appologize..


Quote:
Originally Posted by danmauer
i'm puzzled....

trying to look for the pattern }"'. but the below code returns to me the message below (pattern is curley queue + dbl qt + sng qt + period)




Code:
  
nawk -v pat="\}\"\'\." '
          {
            if (match($0, pat)) {
               before = substr($0,1,RSTART-1);
                 do {
                     pattern = substr($0,RSTART,RLENGTH);
                     printf("%s%s\n", before, pattern);
                     $0=substr($0, RSTART+RLENGTH)
                    } while (match($0, pat))
                 }
          }' $HOME/TEMP/X1.dat >> $HOME/TEMP/X2.dat
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