Shell script to check if any file exists in 4 folders


 
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# 1  
Old 04-02-2009
Shell script to check if any file exists in 4 folders

Hi All,

working on AIX 5.3.

Requirement is:

Shell script in ksh to check if any file exists in 4 folders as below:

1. /FILE/INB/INT1
2. /FILE/INB/INT2
3. /FILE/INB/INT3
4. /FILE/INB/INT4

Thanks a lot for your time!

a1_win.
# 2  
Old 04-02-2009
Quote:
Originally Posted by a1_win
Hi All,

working on AIX 5.3.

Requirement is:

Shell script in ksh to check if any file exists in 4 folders as below:

1. /FILE/INB/INT1
2. /FILE/INB/INT2
3. /FILE/INB/INT3
4. /FILE/INB/INT4

Thanks a lot for your time!

a1_win.
Here is one way

Code:
#!/bin/ksh
#
for dir in 1 2 3 4
do
  cnt=$(ls /FILE/INB/INT{dir} | wc -l)
  if [[ $cnt -ne 0 ]] ; then
    echo "no file in /FILE/INB/INT{dir}"
  fi;
done;

# 3  
Old 04-02-2009

Code:
filecount()
{
  [ -e "$1" ] && numfiles=$# || numfiles=0
}

for dir in /FILE/INB/INT1 /FILE/INB/INT2 /FILE/INB/INT3 /FILE/INB/INT4
do
  filecount "$dir"/*
  if [ $numfiles -gt 0 ]
  then
    printf "%d files in %s\n" "$numfiles" "$dir"
  fi
done

# 4  
Old 04-02-2009
Not sure how find behaves in AIX (or if this counts as a "script"), but...

Code:
 RESULTS = `find ./FILE/INB/INT[1-4] -type f | wc -l` 
 if [ $RESULTS gt 0 ] ; then
   echo "There are $RESULTS files"
 fi

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