Eliminating duplicates from the who command


 
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# 1  
Old 03-17-2009
Data Eliminating duplicates from the who command

I am trying to show how many users are logged into one of my systems. Using who -q it gives me a user count, but some users are logged in multiple times.

Is there any easy parameter that I can use to ignore/eliminate these duplicates??

Thanks
# 2  
Old 03-17-2009
Can you try with who|uniq , see whether you are get rid of dups.

Cheers,
gehlnar
# 3  
Old 03-17-2009
No... no joy :-(,

who|uniq outputted exactly the same as the who command without the pipe.
# 4  
Old 03-17-2009
Code:
who | awk '{ print $1 }' | sort -u

Padow
# 5  
Old 03-17-2009
Hi,

This one also can help.

who | awk '{print $1}' | uniq
# 6  
Old 03-17-2009
Code:
who | cut -f1 -d' ' | sort | uniq

# 7  
Old 03-17-2009
Thanks, that has listed all the unique users, how would I then calculate the amount of users, like who -q shows #users... any thoughts?
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