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multiple search keyword in grep

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# 8  
Old 03-17-2009
Hi Summer, actually you are rite. But what I am seeking for is the previous example.if A: and D: both are found in a line it needs to be shown.
# 9  
Old 03-18-2009
This one may help your need

awk '{if(/A/) {if(/D/) print $0 }}' inputfilename

Thanks
Sha
# 10  
Old 03-19-2009
file contains
A:T00 B:88 C:78 D:00
A:Y00 B:88 C:78
A:T00 B:88 C:78 D:60
A:T00 B:88 C:78

bash-2.05$ awk '{if(/A/) {if(/D/) print $0 }}' multigrep.txt
awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 1
awk: bailing out near line 1
# 11  
Old 03-19-2009
Quote:
Originally Posted by Shahul
This one may help your need

awk '{if(/A/) {if(/D/) print $0 }}' inputfilename

Thanks
Sha
no need explicit "if"s
Code:
awk '/A/ && /D/' file

# 12  
Old 03-19-2009
Hi,

In my System its working good.. Smilie
see my output:
$ cat out.lst
A:T00 B:88 C:78 D:00
A:Y00 B:88 C:78
A:T00 B:88 C:78 D:60
A:T00 B:88 C:78

Code:
$ awk '{if(/A/) {if(/D/) print $0 }}' out.lst
A:T00 B:88 C:78 D:00
A:T00 B:88 C:78 D:60

Or you can use below one as well..

Code:
$ sed -n '/A.*D/p' out.lst
A:T00 B:88 C:78 D:00
A:T00 B:88 C:78 D:60

Code:
$ sed '/A.*D/!d' out.lst
A:T00 B:88 C:78 D:00
A:T00 B:88 C:78 D:60

Code:
$ sed '/A/!d; /D/!d' out.lst
A:T00 B:88 C:78 D:00
A:T00 B:88 C:78 D:60


Thanks
Sha
Last edited by Shahul; 03-19-2009 at 07:46 AM..
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