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substitution in VI editor

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# 1  
Old 03-16-2009
substitution in VI editor
Hi,
I have entries in a log file :

Code:
/tmp/nightly_releases/releases_20090315file1.zip
/tmp/nightly_releases/releases_20090315file2.zip


I want a "/" to be inserted in between directory and the file to complete the path like :

Code:
/tmp/nightly_releases/releases_20090315/file1.zip
/tmp/nightly_releases/releases_20090315/file2.zip

Any script or command for it that i can run from console (not in command promt in VI editor ) please help. Thanks in advance.
Last edited by Yogesh Sawant; 03-25-2009 at 02:06 PM.. Reason: added code tags
# 2  
Old 03-16-2009
try:
Code:
perl -pi -e 's#(releases\_\d+)(file)#\1/\2#' logfile

# 3  
Old 03-16-2009
Thread subject:
Quote:
Originally Posted by bhaskar_m
substitution in VI editor
Quote:
Originally Posted by bhaskar_m
[...](not in command promt in VI editor)[...]
Which one should it be? To do it in VI(m) (as your subject suggests) it would be
Code:
:%s/\(file.\.zip$\)/\/\1/

To do it without VI(m) (as the body of your message suggests), use Yogesh' suggestion, with 2 corrections:
  • There's usually no need to escape an underscore
  • Backrefs (\1, \2) are better written as $1, $2
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