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17,981
Posted By radoulov
The shell field/word splitting occurs only on...
The shell field/word splitting occurs only on expansion.

From the manual pages of bash:


So:

4.1.10(4)-release$ IFS=+
4.1.10(4)-release$ a=( one+two )
4.1.10(4)-release$ echo "${a[0]}"...
751
Posted By itkamaraj
$ nawk -F"[= ]" ' {if($1~/port/) {$6="\$"$1;...
$ nawk -F"[= ]" ' {if($1~/port/) {$6="\$"$1; print $0} else {print $0}} ' test
port1 $PORT && if [ $port1 -eq "$NUM"]; then ........
1,463
Posted By Corona688
That's an interesting request. It's hard to know...
That's an interesting request. It's hard to know your PID in advance!

But not impossible: The exec command can be used to replace your shell's PID with a command. The process being executed...
1,821
Posted By Corona688
I'm not sure what you're trying to do with \s. ...
I'm not sure what you're trying to do with \s. Is that Perl syntax? It's not in POSIX regular expressions.

Remember that the 's/this/that/' syntax replaces the text it matches. It doesn't put...
1,821
Posted By Scrutinizer
Indeed -r is GNU only .... + is not part of...
Indeed -r is GNU only ....

+ is not part of basic regular expressions. You would have to do something like this:
echo "a b c" | sed 's/ \{1,\}/ \& /g'
or this:
echo "a b c" |...
4,164
Posted By anbu23
sed "s/ *[^ ]*/&_label/" file
sed "s/ *[^ ]*/&_label/" file
4,164
Posted By kurumi
$ ruby -ane '$F[1]=$F[1]+"_label";puts $F.join("...
$ ruby -ane '$F[1]=$F[1]+"_label";puts $F.join(" ")' file
$ awk '{$2=$2"_label"}1' file
1,351
Posted By anbu23
paste is expecting filename and not the contents...
paste is expecting filename and not the contents of a file. You can use awk command and remove any lines which dont have "a" and then use paste command

$ cat file1
a 12
b 1
a 3
$ cat file2...
1,211
Posted By Scrutinizer
awk -F: '$4="\""$4"\""' OFS=: infile sed...
awk -F: '$4="\""$4"\""' OFS=: infile
sed 's/\([^:]*\)/"\1"/4' infile
sed 's/:/&"/3;s/:/"&/4' infile

---------- Post updated at 12:58 ---------- Previous update was at 12:38 ----------

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