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Naturally 0.00094 is zero when truncated to three fixed decimal places. That is not "edge case" -- it's supposed to do that.

If you want more decimal points in my code, change DP and MOD.

BASH mandelbrot set:

DP=8
MOD=1
while [[ "${#MOD}" -le "${DP}" ]]
do
MOD="${MOD}0"
done

ESCAPED=0

function ftofix { # ftofix OUTPUTNAME "3.14"
local _N="0"
...

DP=3
MOD=1000

function ftofix { # ftofix OUTPUTNAME "3.14"
local _N="0"
local D=0
local X
local Y

# Convert "VAR" "-.3" into "VAR" "-" "0.3",...

There was a bug in my version above. Arithmetic involving negative numbers worked, the edge case was the display of them. One 'edge' was that I completely forgot to display the sign, at all, ever. ...

Here is the fixed point arithmetic code for a fixed point basic calculator for DASH... Cheers.

#!/bin/bash
# Fixed point arithmetic
DP=3 # Decimal Places
MOD=1000 # 1 * 10^DP

function...

Beware that not only IFS is preserved -- every variable is preserved. Variable assignments inside the new shell don't copy into the old one. It's just like running commands behind a pipe.

I did? It is set -- arg1 arg2 arg3 ... which sets the $1 $2 $3 variables.

If you run it like set -- $variable it will split upon IFS, which is whatever you please, giving an easy way to split a...

I'm sure DASH can divide and multiply absolutely fine. It has * and /.

I noticed, but the way you're doing it is perhaps the hardest possible way. If you just keep your number as an integer,...

Here's a quick bash-only version for positive numbers. The trick is reading the values in. Once you do that the rest is straightforward.

DP=3
MOD=1000

function readnum {
IFS="."...

I misread your post as dash misbehaving rather than zsh, but anyway - I don't mean the shell has floating point. I mean shell printf could use it as a temporary intermediate to implement %f. potato,...

My suggestion would be to eliminate these floating point conversions, and just use integer math. For three decimal points you'd do

SIGN="+"
if [ "$NUM" -lt 0 ]
then
NUM=$((-NUM))
...

Your use of printf "%f" is perhaps begging for trouble, that may convert to floating point and back. And even 64-bit floating point doesn't have the exactness of a 64-bit integer, some of those 64...