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1,630
Posted By nezabudka
I would also replace this construction for i in...
I would also replace this construction
for i in ${3}/$file ; do
i="${i##*/}"
1,630
Posted By nezabudka
it only works with field 5 for i in `ls...
it only works with field 5
for i in `ls $3/$file|cut -d'/' -f5`
do so
for i in $(ls $3/$file | xargs basename -a)

--- Post updated at 10:30 ---

I think you have not correctly defined the...
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