Search Results

egrep -v " +" filename

This will do the trick of removing more than one spaces line also

Regards
JK

I am not getting your problem, it would be nice if you can post your code here

Regards
JK

echo -n "" > somefile

Regards
JK

ps -l pid will show show the status of a process for you besides other things

you can see man page what are the states (R for running and so on )

Regards
JK

Another one is Services For Unix by Microsoft

http://www.microsoft.com/windows/sfu/

Regards
JK

You could very well change the sequence, just read the man page for *date*, it has more informations

date -u +%Y%m%d

data_file is the file in which you have your sequence of dates ie
...

I am not clear with your question, I assume you are asking for today' s date 29122003 to be searched in a file, then the below will work

str=`date -u +%d%m%Y`
grep $str filename

if [ $? -ne 0...

I am really sorry I was just checking the octal value for \n.
Okay any how the program should be like this

echo "Enter answer"
read answer

if [ "$answer" = "" ]
then
echo "You must enter a...

echo "Enter answer"
read answer

echo $answer | od -b

if [ "$answer" = "" ]
then
echo "You must enter a file name"
exit 1
else
cat $answer
fiRegards
JK

added...

ls -l | awk '{ if ($5 < 2000) { print $0 }}'


Regards
JK

I could think of this simple method

i=`ls -1 /tmp /var/tmp | wc -l`

while [ true ]
do
sleep 1
j=`ls -1 /tmp /var/tmp | wc -l`
if [ $j -gt $i ]
then
echo "A...

one more way

echo "" >junk
:D

Regards

Yeah I was very well aware that both of the variable are same, I assumed that he actually wanted a file name which is equivalent to the answer variable

Thanks and Regards
JK

I suppose this is what you were intending to do

Regards
JK

echo " a.read a file"
echo " b.create a file"
echo " c.add on existing file"
echo " d. exit"

while [ true ]
do
echo "Enter...

Yeah that is a workaround that will do,

But I am really wondering how to do the following

suppose I am using getopt function, in a C program and try to caputre the arguments with the -x option...

I wan' t a system call and need not want to tokenize either, I just want to execute the way as normal program does.

./a.out -k abc def -x adf ghi

Regards
JK

Is there a way to get the command line arguments.

I am using getopt(3) but if the arguments are more than one for a particular option than it just ignores the second argument. For eg

./a.out -x...

You can use also this, this is much simpler

find / -name filename | wc -l

Regards
JK

You can try SFU (Services For Unix) by Microsoft also, It is freely available

Regards
JK

find ./ filename | grep -x "filename" | wc -l

It would have been better if you had come with this solution rather than me, just try around and play with unix you can find lot more stuffs and you...

For second query

cp -R JUNK JUNK1

JUNK is the existing directory
JUNK1 is the non-existing directory, if the directory exists then JUNK will be its sub-directory

For third query

find ./...

Well to find out whether a file is executable under a directory, I cannot think of any command as such present in unix, I doubt whether there is any. You can use this script to find out the...

Well I am not too sure what you exactly want the output to be but sort +1 -2 +3 -4 will sort the output based on 2nd field and if second field is same it will see the next specified field in this...

You can try this way also if you want as a single command to be executed one at a time

# export VAR="adafadfadf"
# export LENGTH=`expr "$VAR" : '.*'`
# echo $LENGTH
10
# export VAR=""
#...

# VAR="adfadf"; LENGTH=`expr "$VAR" : '.*'`; echo $LENGTH

I doubt whether your syntax is correct, just use the above it will work correctly


If you want to get 0 for null string put VAR=""
...