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Sorry its not working.



awk -F"\t" '{for (i=2;i<=NF;i++) if (!$i) $i=0}1' OFS="\t" test
output

2015/08/04 00:00:00 171 730579 ...

Yes all the fields are numeric except first one which is date.

the file is tab delimited and actually a output from sql query.

some of the rows are null so u see more space between column where...

hi,

i need to replace a blank tab output in a file to zero.

input file:

2015/08/04 00:00:00 171 730579 27088 ...

can you explain what you want as output?

you can assign simply

y=`echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'`


but not sure what youu mean by variable in a loop

Sorry for not explaining correctly.


Suppose input is :

5 rows in a file with 4 column

2015/07/28 00:00:00 177 445370 ...

but i need to print column too at the same time....
your code will print all the column not specific columns...

I want to print specific range of rows and then its columns using awk command.

lets say if a file contain 15 line then i need to print line 5 to 9.


awk '{print;for( NR>=5&&NR<=9); do; print ...

I got the answer.

below is the code that worked for me.

for((i=0;i<15;i++))
do
if [ "${ZZZLAST_DATAIN_TIME[$i]}" -gt "${ZDATE_1[$i]}" ]
then
echo "YES"
else
echo "no"
fi
done

Hi all,


Currently i am facing issue using if command to compare to array value.

can someone help me?

if [ "${ZZZLAST_DATAIN_TIME[$i]}" -gt "${ZDATE_1[$i]}" ]
then
do
echo "red"
else ...

this is not my homework....its is just i need to learn few skills in unix.....i posted in in homework beacuse i dont get link to post in main forum......as i m new it will take some time for me to...

i need to remove all before 1st space

input :
206292
24436
1115 504
1115 1120793
1115 17453606
62931
547915
108924
305715
23541
19255
315727
1403954
369685...