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Hi I am using -gt comparative operator in one of my shell script.

I have tested that in Linux platform but same code will go in many other platforms i.e.
HPI
HPUX
Solaris
zLinux
...

Thanks Zaxxon for the response.

Yes, we can trap the error and show the message to the user based on the return code.

But I wanted the message which can tell user why it is failed and only...

I have a requirement:

During copy command for example:
cp -rf <sourceDir> <destinationDir>

this command may fails for many reasons like:
1. source or destination directory does not exist
2....

print "After create SubDir routine.";
createSubDirs($fileDir);
my $from = $ORACLE_HOME.$dirSep.$file;
my $to =...

print "After create SubDir routine.";
createSubDirs($fileDir);
my $from = $ORACLE_HOME.$dirSep.$file;
my $to =...

I have appended the keywords as you suggested.

Further I wanted to understand the code better.. can you please help me..
in the below code what does that mean....


@fails = grep...

I have existing pattern in the perl script as:

my $pattern = "^Line.*?:|^Errors*: [^0]|^SEVERE:.*?:|^Null pointer exception occurred";
and I wanted to include below keywords in my search pattern...

Thank you. Problem is solved now. :b:

I am getting below error:

zip error: Nothing to do! (try: zip -rq <zip_name> . -i <file_list>)

if ( ! $_2_zip_dirs eq "" ) {

$OS->print ("$zip -rq $zip2 $_2_zip_dirs\n");
...

What I concluded that all the Linux shell (i.e. sh,bash,ksh) different versions may not support 'typeset' command and may also not considered as standard.

I changed my code:
<<-- BELOW LINE...

I am using ksh only

#!/bin/ksh

typeset -u xname1=$mname1 is working fine in HP-UX.

But it throwing below error in Linux:
line 40: typeset: -u: invalid option
typeset: usage: typeset [-afFirtx] [-p] name[=value] .

Please...

Please share if any one have even a small clue!

We are getting the error below in Linux - Oracle 11g Bench as below:

Last System configure:

NOTE: Fri May 18 17:34:32 IST 2012: creating SPFILE ...
CREATE...

See if your requirement is print or store the unique value of 2nd Column (I assume delimiter is space) the below is your solution:

awk '!A[$2]++{print $0}' abc.txt > def.txt

Thank you sooo much Scrutinizer.

It has worked perfectly the way I wanted... kudos to you.

Can you please explain me the above command, I am bit new to awk.

Thanks Again, Ambar

Thanks Scrutinizer,

I believe you have seen the complete thread conversation to post the above solution, But after itkamaraj suggestion I have changed the way... I am generating only one file now...

Thanks to all readers and specially to itkamaraj...

But I stucked with the below requirement please help me... I wanted the output as:
* I do NOT wanted to sort the command/fourth field...

Kudos to you itkamaraj!!

YOU ARE GOD OF UNIX!!

Thank you sooo much.. itkamaraj.

It worked for me... but can you please explain me
awk -F\| '!/#/{print $4}' SNA_DB_UPG.list | sort -unawk doesn't seems to be working for my shell...

Thanks itkamaraj,

I have to do small change in the code (tiny project)

There is a file name SNA_DB_UPG.list which has a format:

#
#MNT4 ##R9.1.1.4
#R950 ##R9.5.0
#R9501 ##R9.5.0.1...

The output is as below: (running on command prompt)


sys,root # BEGIN { print SNA_DB_UPG.list "|" }
sh: BEGIN: not found.
sys,root # { print $8, "\t", $3}
> END { print " - DONE -" }
>

After removing quotes .. the below code doesn't worked for me....

BEGIN { print SNA_DB_UPG.list "|" }
{ print $8, "\t", $3}
END { print " - DONE -" }

When I executed the below code in command prompt again the same problem.... Seeking for a delimiter and not taking the below as a executable code

BEGIN { print "SNA_DB_UPG.list"," }
{ print $8,...

Now it worked!! Thank you very much...

But can you please elaborate me with the logic as well.. As i am trying to understand the 'AWK'... what is all about - I know it is huge topic but the basic...