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hi ,

how do i remove # from a line where i found regex..

don't need to remove all the line.. only remove comment..

correct that variables contain line numbers.. so

like delete
10 to 13 , and 45 to 47

is there a way with sed to removed more than one set of lines in one line?

so i mean

sed ${firstElem},${lastIndex}d web.xml > web1.xml

this will delete lines between...

is there a way with sed to removed more than one set of lines in one line?

so i mean

sed ${firstElem},${lastIndex}d web.xml > web1.xml

this will delete lines between ...

i ran it like you have specified the output hasn't changed at all.. (substituted MsgBlk with my regex)

thanks .. but i have lots of sections that look like this.. i only need to comment section that has MyRegEx

<filter>
<filter-name>something</filter-name>
...

what do you mean by ?

"using N to get the entire element in /<\([^ >]*\).*<\/\1>/, "

did you try putting space after [[ and before ]] ?

so like this?

if [[ "${File_count}" -gt 0 && "${File_flag}" == "Y" ]]

hi,
i need my bash script to find regex in xml file.. and comment 2 lines before and after the line that contains regex.. can't use # needs to be <!-- at the beginning and --> and the end of the...