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Thanks for all you suggestions,
i'm my haste I did not make it clear what my end required result was.

whilst reading through the list I need to capture the text between each individual ##START##...

I have a list in the format below, how do I read through the list and extract the lines between the ##START## and ##END##, so i can check for specific values between each ##START## & ##END##...

I'm attempting to replace a substring that contains a hyphen and not having much success, can anyone point out where i'm going wrong or suggest an alternative.


[root@localhost kvm]# echo...

I'd like to list all ports and the services allocated to them:
1) What commands will do this on Solaris 10 and Linux?
2) Is there a file containing the port/service mapping?

Can anyone suggest a workaround


zone_5.org='/qaz/qwe/path/tns.osn'


output
/home/bingo/XXX_script.sh: line 180: zone_5.org=/qaz/qwe/path/tns.osn: no parent

The path does not exist on the...

I've made a number of errors with this and am trying to work a solution within the same framework.

/bin/ksh
for host_name in ahost1 ahost2 bhost1 bhost2
do
for host_prefix in a b
do
...

nawk gives the same response as awk

$ df -h | awk '$5 > 75 {print}'
Filesystem size used avail capacity Mounted on
a/b/c/ 20G 1.4G 18G 8% /blah/blah
w/x/y ...

Running solaris 9, on issuing the follwing command
df -h | awk '$5 > 45 {print}'
Filesystems with utilisation > 45% are being displayed as well as those between
5 and-9%!!!

I still get the password prompt,

when the following command is issued the command prompt is received, how do I get past this?

ssh -t usera@hosta sudo su - userb -c id

Thanks,
I have a few more directories to search on the host, that's why I attempted to do it via a here doc

The code below works ok, however; I need to output the results to a local variable



the_path="/mnt/back/hang"
ssh -T -i /home/buddy/.ssh/id_rsa buddy@ginger << EOF
find ${the_path} -name...

Trying to insert a backspace for echo.


while true ; do
i='-\|/'
for j in 1 2 3 4
do
echo -ne "$(echo ${i} | cut -c${j})"
sleep 1
done
done

this currently outputs:
-\|/-\|/-\|/-\|...

I've tested both variants successfully using the korn shell.

what is the difference between using

$(cat <<MENU...

&

$(<<MENU...

dumb question, but what's the difference between the back quotes and parentheses?

O/S solaris 9
shell ksh


if [ ! `uptime | grep day` ]
then
chk_op[0]="WARNING...reboot within the last 24hrs, restarted at `who -r | awk '{print $4$5"@"$6}'`" ;
else
if [ `uptime |...

sorry i've framed my question incorrectly.

I need to grep a file for a pattern and output the non matching part of the line

a file containing
https://www.amazon.com
Help.com (http://www.help.com)
https://www.google.com
http///www.bbc.com
grep -o 'https://' filename....... print non matching part of output

is it possible to reverse the output of grep -o

Thanks, that exactly what I was after.

---------- Post updated at 12:57 PM ---------- Previous update was at 12:45 PM ----------

if an arrays contents where

array[0]="the quick"...

ksh
eg
arrayname=(1 2 3 4 5)

I'm trying to display the individual contents of an array on a new line without using a loop, using one line of code.

output
1
2
3
4
5

korn shell,

testing if a pattern exist in a string,
x is constant, y could be none,all or any combination of the elements of x,

x="aa bb cc dd ee ff gg hh ii jj kk ll"
y="ff kk"
for z in...

I'm in the process of writng a function that consists of a case statement is there a way of calling the function and passing a value to it?

ie

function1 () {
case
opt1 do .....
opt2 do........

Using the case statement was my fallback solution.