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Friends,

I have data sorted on id like this

id addressl
1 abc
2 abc
2 abc
2 abc
3 aabc
4 abc
4 abc

I want to pick all ids with addressesses leaving out duplicate records. Desired...

try this

grep -F $A *.txt

try this:
awk -F"mdn" "{a[NR]=$0}/WARNING/{$0=a[NR-4];print substr($2,2,9)}" file | sort | uniq

printf "%s\n%s\n" 10,250.00 20,103.15 | awk '{var=$1;gsub(/,/,x,var);print var}'
printf "%s\n%s\n" 10,250.00 20,103.15 | awk '{gsub(/,/,x,$1);print $1}'
both gave same result, sir.
Thank you

Thanks. One more query. Is it possible to assign the result of gsub to a variable?
like
var=gsub(/,/,"",$1)

I am using awk to sum up all amounts and at end print total.

input:
10,250.00
20,103.15


expected output:
30353.15

code:
{subtot=+$1} END{print subtot}

The problem I encounter is it...

sir,

code
awk '/Output view:/{f=1; $0=$0 p; p=x} !f{p=p RS $0} f' file

works fine. But can you explain me step by step by step how it works.

CAN YOU PLEASE EXPLAIN WHAT {A[$1]++" EXACTLY " DOES? IT IS CREATING AN ARRAY BUT NOT ASSIGNING ANYTHING. FURTHER INCREMENT SIGN IS NOT UNDERSTOOD BY ME. PLEASE HELP ME UNDERSTAND THIS.

No...

grep "human" infile | awk ' { for (i=1;i<=NF;i++)
if(($i) ~ /name=/) count[$i]++}
END { print "human = "NR;
for (a in count)
{ t=length(a)-6; print substr(a,6,t),"=",count[a]}}'

try this

cat infile | awk " {rec[$1]=$1;c[$1]++} END { for (a in rec) print rec[a],c[a]} "

try this awk ( stored in a file)

{rec=$0;endthis=1;this=1;len=length(rec)/2}
END { while (endthis<len+1)
printf("%s\n",substr(rec,this,100));
this+=100;endithis++;}}

echo a,b,c,d,e,f,g,h,i | awk 'NR>5 && $1~/f/ {print "yes"}' RS=,

I guest $5~/f/ { print $0 } would print the record if the fifth column has f in it.

Than you. This worked. But one thing I wanted to know,
my code looks fine, but returns nothing. If someone can help me
understand how array is handled here, it will help me with other such...

Dear friends,

I have two files. One with all IDs(in a single field) . And another with data(of which say field 5 is ID). I want to create an array of IDs using first file and
while reading...

Thank you very much. The problem was elsewhere and my focus in some other place.
This changed set my problem right. Thanks a lot

Since there are four record to match with array, the result I expect is four or less. But the awk returns 8 records, and I did not follow how. I had in mind the following result

20
30
...

i have two files say a and b
a has these lines

1 20 30 40
2 30 40 50
3 25 35 45
5 20 50 20


and b has these lines


20 30
30 40
25 35
20 50

the script reads
FILENAME ( "a" )...

If you want the line to be printed where second column begins with 33
try this
awk ' { if (substr($2,1,2)==33) print $0 } ' filename

if you want to print only that column say print $2

A...

some homework and got the solution.

my default shell interpreter is bsh/sh
adding a line at the beginning was the trick
SHELL=/bin/ksh


thank u anyway

#my script is file named "q" and input comes from file named "file1"
paste <(cut -c37-42 file1) <(cut -c43-53 file1 |amtawk )
q: syntax error at line 1: `(' unexpected
"paste <(cut -c37-42...

when i give this command at prompt it works
paste <(cut -f1 file1) <(cut -f3 file2) | someawkscript
but when the same is addex to any shell script and run it does not work
the erro is at (
even...

a=2
b=9
c='echo $a+$b | bc'
echo $c


this should work

a=2
b=3
c='echo $a+$b | bc'
echo $c


# two variables with operator + in between are echoed as a string
and passed on to bc to evaluate, which is stored in variable c.

i have pleasure in using shell scripts and vi editor.
VI Improved on Linux is also good.
Is there a way that allows using shell as command interpretor
and VIm as editor to work on windows? (not...

use expr instead
if u have variables a and b
c=` expr $a+$b `