Search Results

Thanks a lot dear.
It works .

Dear All,

Need the logic in awk to match a pattern in a file and insert a line above and below the matched pattern.

Eg:
cat text;
09/04/2010
10/04/2010
11/04/2010

I want to match...

I am getting the following error,

P01:~$sed -i 's/^PRODUCTIVITY$/Reminder1\n\1reminder2/' servernotification.txt
sed: Not a recognized flag: i
Usage: sed [-n] Script [File ...]
sed...

Dear All,

Hv a very specific requirement.

I have a very large text file and in which I have to match a pattern and insert a line above and below.

Eg:

My file

cat test
date1
date2...

The data is in a oracle table.

---------- Post updated at 06:32 PM ---------- Previous update was at 06:31 PM ----------

Neo request you to help me ...

Dear Team,

How do we match two patterns on the same line using awk?Are there any logical operators which i could use in awk like awk '\gokul && chennai\' <filename>

Eg:

Input file:
...

ope the file in vi editor

1.hit esc .
2. Type %s/"pattern to be matched"/"pattern to be replaced"/g

This will replace all the instances of pattern to be matched

Dear Friends,

Am an newbie to this domain. I have a table which is filled with contents which i need to be updated with,so am trying to design a flow which would read the data from the table and...

Thank you nimish for your reply.

I did not have to permission to push through into....

Anyways thanks a lot.......

Do we have any way to find when the crontab entry was last edited?:)

go to that particular directory where your files reside.

ls -lart | grep 'Dec 24' | awk {' print $5'} | xargs rm

hi everybody.
please help me in understanding this code.



echo "************* starting job on `date +\"%d/%m/%Y at %T\"` **************"
#
scriptdir=`dirname $0`
....