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Hi,

I 'd like to translate this command from awk to findstr on Windows DOS

FILE:

str1 server1 a
str1 server2 a
str2 server1 b
str2 server2 b

Awk command:
awk ' $1 ~/str1/ {...

syntax error as follow:

awk: syntax error near line 1
awk: bailing out near line 1


Probably typo error

command as follow:

awk ' $1 ~ HOSTNAME { print $2 } ' HOSTNAME="${HOSTNAME}" text1

Thank you all.

I am trying to run awk in finish script after jumpstart installation on Solaris 10 X86.
The boot image during jumpstart does not have awk in /usr/xpg4.

And it doesn't work if I...

Hi,

Pass variable in SUN SOLARIS awk

I have a file call text

server1 10.0.0.2

When i use this awk command in Mac OS and Linux , everything works as expected.

export...

Thank you very much to all , awk array is a power tool.

Hi,

I am trying to count the max number of occurences of field1 in my apache log

example:

10.0.0.1 field2 field3
10.0.0.2 filed2 field3
10.0.0.1 field2 field3
10.0.0.1 field2 field3
...

Thanks that works well

May I ask where can read on reference for

f{$0 = "#" $0} ?

Hello,

I have a file as follow

a
b
c
c
d
d
e


I would like to write a awk command to insert # from the first occurence of
"c" to the end of the files.
OUTPUT should be like this
...

thanks

Hi,

Example

^www\.[^.]+\.host\.com$

I would like to know what the bold parts means.

thanks

Thanks!

for loop does solve the issue.

Hi,

I 'd like have a script to ssh to a list of hosts from a file name hosts_list. However, the script seem to exit out from the first line of the file

#!/bin/bash
X="hosts_list";

while...

thank you much

Hi,

I am interesting in writing the following bash codes into perl

My script is simple take field 2 in /etc/passwd and put into an array

#!/bin/bash
PASSWD_FILE=/etc/passwd
A=(`awk -F: ' {...

Hi,

I have a file

1:apple orange:one
2:banana:two
3:cherry:3

When I do awk -F: ' { print $2 } ' file

apple orange
banana
cherry

Now, when i redirect awk output to the file it has...

I got the answer to this question

awk -F: '$1~/username/ { x=$0 ; next ; } ($1~/pass_expir/) && ($2 > 3 ) { printf x"\n" $0"\n" ;}' file

Hello,

I have a file format like this

username: user1
pass_expir: 3
username: user2
pass_expir: 4
username: user3
pass_expir: 0

I 'd like to use awk to print out username and...

Hi,

We found something on google, and it works

df -kP | awk ' BEGIN { FS="[ %\t]+" ; } { print $5 ; } '

Hi,

I am expecting the output to eliminate %. That's why I place % as one of my field separator.

Thanks for the input though.

Hi,

I would like to get 5th field from this output using FS[ %].

Filesystem 1024-blocks Used Available Capacity Mounted on
172.29.138.222:/vol/vol0 311936256 2565248 309371008 ...

I have a passwd file

user:me31oe0ZEh:100:100: user name ++user@domain.com:/export/user:/bin/bash

to get the 6field and awk again with email address.

current command

awk -F":" ' { print...

thank you much, this exactly what I need.

actually, I want the output appear like this:

a:work:apple1
b:baby:banana2
c:candy:cat3

Thanks

thank you for your quick post. I was wondering if this can be done with awk ?

I would like to do the following in bash shell.

file a

a:1
b:2
c:3

file b

a:work:apple
b:baby:banana
c:candy:cat
d:desk:dog

I would like to match field 1 in file a to file b, if...