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I have a variable with the date stored in the format MMDDhhmmYY and i cant change that i just have to work from that

btw all im really looking for is an idea of how to solve this rather than actual code.

Thanks

i need to compare to dates/times given in the format MMDDhhmmYY. That is month, day, hour, minute, year. It is a 24 hour clock. I need to compare two dates to check that they are, say, less than 900...

thanks. its always the little things!

I need to multiply the value of a variable and then store it in another variable. I have EXPHOURINSEC=$(($EXPDATEHOUR * 3600)) but i get an error saying the * is unexpected.

Im using ksh

yeh i was being a bit special there! thanks

my problem isnt with getting to the numbers (altho your suggestions are nicer!). The code i used with sed got the numbers but it doesnt seem to store them in the new variables. when i run the script...

Here is my code:

DATETIME=1214163003

echo $DATETIME | sed 's/....//' | sed 's/....$//' | read DATEHOUR
echo $DATETIME | sed 's/......//' | sed 's/..$//' | read DATEMIN

echo $DATEHOUR
echo...

thats great thanks

thanks. now how do i store the output of that to either HOUR again or a new variable?

I need to replace the first character of a variable but only if it is a 0. For example i have a variable called HOUR and when its value is 01, 02, etc i need to just get rid of the 0. however when...