Programming

Originally Posted by era

filename[0] is the first character of the string. If the string is empty, the first character will be the terminator null byte.

C string-handling functions generally cannot read past a null byte. Your notation " ", `\0` is extremely non-standard, and seems to correspond to a string consisting of a space, followed by a null byte (which is usually not explicitly marked or required; it's the end of string, plain and simple). That string obviously has a length of one.

The C equality operator == does not compare strings in any meaningful way; you need to use a function such as strcmp. (I too thought this was shocking when I was learning C.) You can compare individual single characters (denoted by single quotes) one by one, which is what strcmp basically does in a loop over the strings it compares. Double quotes are used around strings (character arrays).

The C string tutorial which was already pointed out to you once probably explains all of this a lot better. Please read it.

Originally Posted by amitpansuria

I m doing programming in c using linux.

I have one character array filename of 126 size.

now during developping my module I have situation where
I got filename = " ",`\0`

Now I want to check for this condtion

I have try following option but it didnot work

(1)
int len;
if (filename == " ",`\0` )
{
len =0;
}

(2) int len;

if ( strcmp(filename, " " ",`\0`") )
{
len = 0;
}

both method are not working

can you tell me how do I check filename = " ",`\0' condition

Regards,
Amit