The C language, the C preprocessor, and the linker do not work that way.
Besides, altering what you stuff into a pair of double quotes doesn't move it into the code segment. It will be in the data segment, just like before, when he couldn't find it.
To stuff non-code content into the code segment, assembly language might be required.
You could try inline assembler inside your C code using a simple short jump to a NOP and filling the gap with define bytes with the hex values of the string you want to display:
Pseudo-code...
Code:
Enter the C _asm_ extension statement inside the beginning of _main_.
jmp short LABEL:
db 0x??
db 0x??
.
.
db 0x??
LABEL:
nop
Close assembler statement and continue.
This will safely give 120 characters worth of define byte[s], 'db'.
Where ?? are the hex values of the characters.
It might work under gcc...
I have no idea if this would work under gcc, (it does work on C compilers on other older platforms).
------ Post updated at 09:46 PM ------
This might attach itself to the previous code:
Code:
#include <stdio.h>
int main(void)
{
/* This should be inside this assembler code. */
asm ("jmp getout;"
"useless: .asciz \"Barry Walker!\n\";"
"getout:;"
"nop;"
);
printf("This should be in the data section.\n");
printf("Testing the hidden string.\n");
return 0;
}
Results OSX 10.13.6, default bash terminal compiled under gcc.
The JMP instruction is at the end of the upper line and is this: e9 0f 00 00 00 followed by the characters.
'e9' is jmp op-code.
'0f' is the little endian number of bytes, (from a signed 32 bit number), 15 decimal, to jump to the end-of-file/null byte '00' to execute the nop op-code.
Hope this helps too.
Last edited by wisecracker; 10-28-2018 at 07:28 PM..
Reason: Pointed out the jmp instruction.
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10-28-2018
