predict the output


 
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# 1  
Old 10-17-2005
Question predict the output

Predict output of the following program:

void func()
{
int a[1];
a[2]+=17;
}

int main(void)
{
char s[] = "hello\n";
func();
printf("%s",s);
return 0;
}


run program in linux :
# 2  
Old 10-17-2005
no output

i tried..but no output
# 3  
Old 10-17-2005
Looks like homework to me.
# 4  
Old 10-18-2005
Quote:
Originally Posted by hareesh
Predict output of the following program:

void func()
{
int a[1];
a[2]+=17;
}

int main(void)
{
char s[] = "hello\n";
func();
printf("%s",s);
return 0;
}


run program in linux :

Program prints hello. What were u expecting ?
# 5  
Old 10-18-2005
Quote:
Originally Posted by parasa
Program prints hello. What were u expecting ?
This is not portable code. Use it exactly as given, do not correct the code in any way. You must use Linux running on an IA-32 architecture. Compile it with gcc, like this:
gcc bogus.c -o bogus
and then run it like this:
./bogus
# 6  
Old 10-18-2005
I have copied it as it is, complied as described, but still the same.

What is the output on your side ?
# 7  
Old 10-18-2005
"int a[1];
a[2]+=17;"

Its clearly violating the basic rules of array declaration...
But again, wats the purpose of this question???


abey.
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