Problem with system("command")

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# 1  
Old 10-11-2010
Problem with system("command")

Sorry, I don't speak English very well but I will try to explain my problem!
If I write a C++ program and I use che system call system("command") I have this problem:

If I would launch a program I do this:

and all work fine!!

But if I divide this command in two part like these:
system(cd ~/Agostino/program/);

no work fine because "test" is not found. "test" is searched in the default home path. The second call to system is executed like if it was invoked in another terminal session!

I showed this trivial example but, generally, I would that the second call to system start when the first terminated and as a result.

I hope I've explained well my problem! Thank you all for your cooperation!
# 2  
Old 10-11-2010
The system() function runs the command in a separate process. When you run a second call, it gets its own process and anything (environment, working directory etc.) set in the first process isn't available.

Try putting the two commands together
system( "cd ~/Agostino/program; test" );

This will change directories and then run the test command; all in the same process.

Hope this helps.

---------- Post updated at 21:04 ---------- Previous update was at 20:58 ----------

It occurs to me that the system() function usually executes /bin/sh, and depending on your environment the shell installed as /bin/sh might not support the [/code]~[/icode] as meaning "home directory." Best to pass that information into your programme, or have the programme use get the value of HOME from the environment and use it.
# 3  
Old 10-11-2010
Thanks a lot!!
I will test it when arrive at home!!
And IfI want to spend some time between the first and the second command?? I would be sure that the first command is completed before the beginning of the second.
# 4  
Old 10-11-2010
Originally Posted by acciues
Thanks a lot!!
I will test it when arrive at home!!
And IfI want to spend some time between the first and the second command?? I would be sure that the first command is completed before the beginning of the second.
Yes, the syntax command1; command2 'blocks' until the first command has completed. You could try this from the command line and see the behaviour:
date; sleep 4; date

# 5  
Old 10-11-2010
It work fine!! But I have other problem!!

This is my code:
#include <iostream>
#include <cstdlib>
#include <string>
#include <fstream>

using namespace std;

int main (int argc, char* argv[]) {
	system("scp file.pdf AgostinoPolizzano@; ssh AgostinoPolizzano@; cmd");
	return 0;

If I execute it, this is the output:
Last login: Tue Oct 12 03:49:13 on ttys000
MacBook-Pro-di-Agostino-Polizzano:~ AgostinoPolizzano$ ./test
file.pdf                                      100%  331KB 331.3KB/s   00:00    
Last login: Tue Oct 12 03:49:39 2010 from

AgostinoPolizzano@SERVER ~

The third command does not run and the program stops at the end of the second command!! Why?? It's a SSH question??
Thanks a lot!!
# 6  
Old 10-11-2010
What exactly is "cmd" supposed to do? It's not any UNIX command I've ever heard of.

If you're trying to run it on the remote server there shouldn't be a ; between it and the ssh command, since it will try to run it locally once ssh has finished, not inside ssh!
# 7  
Old 10-11-2010
cmd is Window's Command Prompt!! The ssh connection is between a Windows Server (OpenSSH is emulated by CygWin) and MacOs or Linux (is the same!!!!).

This command
system("scp file.pdf AgostinoPolizzano@; ssh AgostinoPolizzano@ cmd");

work fine!!!

Missing the last command that interests me and we have finished!!! It launch a print job on the server:
start C:\"Program Files"\Adobe\"Reader 9.0"\Reader\AcroRd32.exe /p /h file.pdf

How can I launch the last command after "cmd"???

Thanks very very much!!
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