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How i can read a long integer from standar input and a string with as many characters as specified..

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# 1  
Old 10-15-2009
How i can read a long integer from standar input and a string with as many characters as specified..
how i can read a long integer from standar input and a string with as many characters as specified in the number?

i thing that i must use the read command ofcourse....
# 2  
Old 10-15-2009
Code:
#include <stdlib.h>
#include <stdio.h>

int main( int argc, char **argv )
{
    int    num;
    char    format[ 8 ];
    char    inps[ 100 ];

    scanf( "%d ", &num );
    sprintf( format, "%%%ds", num );
    scanf( format, inps );
    printf( "format: '%s' -- num: %d, text: %s\n", format, num, inps );
    return( 0 );
}

# 3  
Old 10-15-2009
thnx you...


but i want to achieve this with the read command and in combination with malloc... is that possible?
# 4  
Old 10-15-2009
What is the malloc supposed to be used for? Why so specific, is this an assignment?
# 5  
Old 10-15-2009
I suppose that it might be possible but it would make more sense to use something like getchar() and have a loop like so:

while ( ( c = getchar() ) != EOF )
{
...
}

or use gets();

I am not sure of your reasons but it doesn't seem practical to use read() to read from stdin, unless I am missing something obvious.

Julian
# 6  
Old 10-15-2009
its not an assignment, its for an exercise....but i dont know how to do it with read
its something like this. read (STDIN, BUFFER, SIZE)

but the i dont know how to continue, ok


printf("GIVE NUMBER");
i = read (STDIN, BUFFER, SIZE);

with pointers after or whatever...

something like this....
# 7  
Old 10-15-2009
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