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Getting File Name


 
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# 1  
Old 10-13-2003
Getting File Name

Hi!

I'm developing an application program by C++ language in the UNIX environment and I would know the name of last file written at a particular path and with a particular prefix.
For instance, I need someting like output of following UNIX pipelined command:

ls -t $PATHFILE/file_prefix_* | head -1

How can I achieve the same result in C++? I tried with the system call:

system( "ls -t $PATHFILE/file_prefix_* | head -1 > tmpfile" );

In this way I saved filename I'm looking for in tmpfile, but I don't think it is a good solution.

Many thanks. Bye,
Paride
# 2  
Old 10-13-2003
You can use readdir() to read a directory. Then use lstat() on each file.
# 3  
Old 10-23-2003
OK

Many thanks! My application is working!

Bye,
Paride
# 4  
Old 10-24-2003
Quote:
Originally posted by Perderabo
You can use readdir() to read a directory. Then use lstat() on each file.
That is definately more reliable than a tmp file, but another solution - just for giggles - would be to use popen on the command and avoid the temp file, reading the output of the ls command directly through the pipe.

Just a thought...popen is not the best solution in this case - given the various shells aliases and things could preclude the ls from functioning as desired - but popen is a nice thing to explore.
# 5  
Old 10-24-2003
It's not the temp file that bothers me. It's the extra processes. First you launch a shell. It reads a command line. It launches a pair of processes. Then you read the temp file.

Now compare that to just reading the directory.

And popen() is not much better.

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