Programming

I have a special character called ô. When it is declared as a character variable its showing it can be printed. But when it is declared as a character pointer variable its showing it cannot be printed. I am just wondering why its happening like this..

c1 = '@';
c2 = 'ô';
char *fp;
fp="XXô";

if ( isprint(c1) )
printf ("%c can be printed \n ", c1);
else
printf ("%c cannot be printed \n ", c1);
if ( isprint(c2) )
printf ("%c can be printed \n ", c2);
else
printf ("%c cannot be printed \n ", c2);

while (*fp){

if ( isprint(*fp)) )
{
printf ("%s can be printed \n ", fp);
fp++;
}
else
{
printf ("%s cannot be printed \n ", fp);
fp++;
}
}


This is my sample code...If I remove the pointer declaration and print the character alone its showing it can be printed. If I include the pointer declaration and try to print it from the pointer its showing it cannot be printed.,..please advise on this..

output:

Code:

> cc ptest.c
> a.out
 @ is printable
 ô is not printable
 X is printable
 X is printable
 ô is not printable

Code:

> cat ptest.c

void printable(char ch)
{
  printf(" %c %s printable\n", ch, (isprint( (int) ch)) ? "is" : "is not");
}

int main()
{
    char c1 = '@';
    char c2 = 'ô';
    char  *fp="XXô";
    char *p=fp;
    printable(c1);
    printable(c2);
    for(p=fp; *p; p++) printable(*p);
    return 0;
}

Your code has problems.