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GNU grep (/usr/sfw/bin/ggrep) is generally installed at system in /usr/sfw/bin.

okay if you are not using GNU find then i guess maxdepth will not be available.

You can do something like below using prune to not descending to and directory other than "dir".
find...

try using printf. :)

prstat 1 1 | awk '{printf ("%10s %10s %10s %10s\n",$1,$2,$9,$10)}'

okay, the below cron entry will get file once daily at 8:30 pm.

30 20 * * * /home/test/scripts/example.sh

the gnu find has a maxdepth option that lets you restrict the search to the current directory.

can you try something like below.

find . -maxdepth 1 -mtime +30

you can find the files older than 30 days and archive them with the below commandline.

find . -mtime +30 | xargs tar cvzf archive.tar

remove files older than 30 days with the below commandline....

try
sed "s/Winston (UK) Wong/7000/" tmp0.txt

You can use associative arrays like below ,

awk -F"," '{math[$9]+=$22;}END{for (i in math) {print i,math[i]}}' sampleInput.txt

echo "you are how Hi" | awk 'BEGIN{RS=" ";ORS=" "}{arr[NR-1]=$1;num++}END{for (i=num-1;i>=0;i--)print arr[i]}'

regular expressions are not part of Standard C, you might find some
libraries for it. All i can suggest is searching for PCRE might give you something .

You can also edit the /etc/sudoers file and allow specific users to shutdown or reboot the system .Something like that .
## Allows members of the users group to shutdown this system
# %users ...

use ls with find , something like below .

find "/abc/xyz/pqr/$INPUTDIR" -type f -ls

Does the below suffice your requirement ?
Result=$(echo "Absoulte_Markup_XYZ.xml" | cut -d "." -f1 | awk -F "_" '{print $NF}')

Hello friend ,
You need to modify your looping part as below

for i in $(ls *-.sql)
do
((n++))
done
echo "Number of conversions is $n"

Hello ,
You want to do something like that . huh?
for CLIENT in $(cat clientlist)
do
for POLICY in $(bppllist -byclient $CLIENT | grep "CLASS " | awk '{print $2}')
do
...

Try something like

ps -eo pri,psr,pcpu,stat | awk '{if($3 >= 25)print $0}'

Hello Bala ,

In addition to your solution , i would like to add the increment part of index , can also be done below .

((i+=1))

instead of using -v switch to pass the SHELL variable to the awklet ,you can use like below .

awk '$1==a' a=$NU input-file

Associative arrays are just live savers in these needs

awk '{arr[$1]++}END{for (i in arr) {print i "-" arr[i]}}' uniq.dat

egrep or grep with an 'e' switch can also serve your purpose .

grep -e $trans -e $reason file

OR

egrep ($trans| $reason) file

Dear friend ,
Can you please let us know if the below command line satisfies your requirement ?


echo "/5/6/7" | awk -F "/" '{for (i=1;i<=NF;i++){if (i==1){continue}printf " -k " $i "n"}}'

Please try this below command line , i am not currently in a unix box .

find . -type f -exec ls -1 {} \; | awk -F "/" '{ print $NF }'

Hello Aish11 ,

In order to remove the % symbol in your sample input file use

for i in `cat df_fnl.txt | sed 's/%//g'`

Does the below code segment is what you need ?

df_threshold=90;...