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sed only:
sed -rn 's/^ *| *$//; / *\\Start/,/^$/ {H; /^$/ {g;s/\n//g;p;s/.*//;h; };}; $ {g;s/\n//g;p;}' file
\Start\now\fine stepwatch this space for tools ends here
\Start\then\go language...

Try:
awk '/\\Start/{f=1} !NF{if(f)print s; s=x; f=0} f{s=s $0} END{if(f) print s}' file
\Start\now\fine step watch this space for tools ends here
\Start\then\go language again cubernates...

You can try this, it is probably a lot more complicated that in needs to be but it seems to work. It trims the leading spaces before \Start as well so if that is undesired then it can be changed.
...

Its more how you used your zip tool you should look to find why you have PATH included... and htta you dont mention...

Hello krsnadasa,

Following is the explanation for above code, hope it may help you in same.

awk -F"|" ' ######## Making field seprator as |
!arr[$1]++ ...

${f} is the same that $f, the variable, right?
There are two parts in shell expansion ${f%.*}, the `%' and the glob pattern `.*' (this is not a regular expression), in this case a dot followed by...

man bash:

Actually, it's a grep version. The sed command just makes sure grep is working on the first field by adding the needed regex parts (no spaces up to the name, trailing space).

How about sed 's/^/^[^ ]*/;s/$/ /' pattern | grep -f- content

I have been trying to solve this through sed.
inline!
sed -n -e '/\@{sed -e '1p' pattern.txt}/p' content.txtAlso tried curlys with many other combination, just can't get it working.
I Like the...

An Awk version
awk '
FNR==NR { # prevents loading Content.txt into array s
s[$0] # load Pattern.txt file into array s
next ...

How about:


#!/bin/sh

#awkcode=`sed 's,\(.*\),$1 ~ /\1/ { print $0 },' <Pattern.txt`
awkcode=`sed 's,\(.*\),$1 ~ /@\1$/ { print $0 },' <Pattern.txt`

awk "
$awkcode
" <Content.txt

...

Try awk 'NR==1 {n = split (KW, TMP, ",")
for (; n>0; n--) PAT[TMP[n]]
}
{T=$1; sub (/^ */, "", T)}
T...

Hello krsnadasa,

Following may help you, could you please check and let me know.

awk '{gsub(/^ +/,X,$0);n = split (KW, TMP, ",")
for (; n>0; n--) PAT[TMP[n]]
...

Trydf -kh .|awk 'NR==1 {split($0,B);next} {for (i=1;i<=NF;i++) print B[i],"-->",$i}'

Hi

You should source the script, not run the script like a command.

if in bash:
$ source script_name

for ksh:
. scriptname

Moreover, the script may not help you much since the...

Yes, the comma is needed to make use of OFS.
No, it will not "default" as a space but if the 2 fields are "glued" together in the print statement without the comma, the output will also be "glued"...

sed will never match a "terminal" new-line. To make it match a "terminal" new-line, you need to create a multi-line pattern space so that the "terminal" new-line of first line becomes an "embedded"...

Hey Hi..

v[$3] is the key here. It stores the current line, before store the current line we are having previous line.

Example1:
1234|1|Jon|some text|some text
1234|2|Jon|some text|some...

I think I wrote that a bit quickly. It is correct, but probably this equivalent code is probably somewhat easier to understand:
awk '$2{print RS $0}' FS='\n' RS=\> ORS= infile
This means:

use...

Because that means something else. In awk language that means:
"print a string that consists of the variables i and to and the array element A[""]"
, which all are uninitialized and so an empty...

-F"[><]" --> we are giving two field seperator >< ( if any one occurs, then field will be seperated )

Sure:
awk ' # For every line in file2
getline p<f { # if reading the next line from the file in variable f (containing the name of file1) into variable p is successful
...

cat FILE | paste - - | sed 's/ Name//'

a=$1 --> a will hold the first field
a=a""substr($2,length($2)-1,length($1)) --> append the last character of second filed with a
getline --> read the next line ( so that $0 will be having the...