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find . -type f \( -name '*.jpeg' -o -name '*.gif' -o -name '*.bmp' -o -name '*.tiff' -o -name '*.png' \) -exec mogrify -format jpg {} \; -delete


--ahamed

Use -e with the echo in the above code as in echo -e "$output"

Or another approach

#!/bin/bash

read -p "Please enter a name : " name
awk -F":" '
BEGIN{ fmt="%20s%20s\n" }
function...

This is not right. Did you try the code which I gave to see if it works for you without integrating it to your script?
I think what you are trying to do here is, get a input and display the details...

I suppose this is what you are looking for

awk -F, 'BEGIN{
printf("%-20s%-20s%-20s%-20s\n", "Month", "No of files", "Total no of sucess", "Total no of failure")
}
file !=...

Thats right!

I get the output though with the input you have given.
Check if this is correct. Which is your OS?

root@maximus-netpune-21:/tmp# awk '{
> status=substr($0,91,2)
> ...

I made the changes in 2 places, did you try with the code which I posted in #6?

Try this
df -h | awk '$5+0 > 45'
If it doesn't work, provide the output of df -h

And in Solaris, use nawk

mystr is basically having the address. And when you do mystr = "Hello..."; you are altering the address rather than modifying the content in that address.

Try this...
awk '{
status=substr($0,91,2)
ind=substr($0,26,1);
split(substr($0, 11, 24-11), val,/\.0 /);
key[NR%2":"val[1]val[2]] = ind":"status
}
END{
...

Exporting this makes the date/time available in the history command

HISTTIMEFORMAT="%d/%m/%y %T"


Well, not sure how old this is though.

Similar GNU awk approach

gawk -F'##' '
{
then=mktime(substr($2,1,4)" "substr($2,5,2)" "substr($2,7,2)" "substr($2,9,2)" "substr($2,11,2)" 0")
}
now > then
' now=$(date '+%s')...

Try this

awk '{
status=substr($0,91,2)
ind=substr($0,26,1);
split(substr($0, 11, 24-11), val,/\.0 /);
key[NR%2":"val[1]val[2]] = ind":"status
}
END{
...

I have corrected the code.
Its kind of difficult to code and post via mobile/tablet ;)

The grep command is getting 2 values for tellabs7100

0 for tellabs7100
30 for tellabs7100N

and that is why the value 0^J30 is seen, ^J is actually unix line feed.

Since grep-ing for...

Please correct the code tags, it is difficult to read.
Also, paste the output of sh -x yourscript

awk 'NR==FNR{A[$4]=$0; next} $6 in A{ print A[$6]"\t"$0 }' file1 file2

You should not echo it, what i gave was an example.Try this...

sshpass -p 'password' ssh -o StrictHostKeyChecking=no root@storageip 'isi_for_array -s \"isi auth ads time --sync --force\" '
...

Use the -exec option then


find /prodoragridcn_01/app/oracle/product/10204/rdbms/audit/ -name "*.aud" -type f -mtime +60 -exec rm {} \;


--ahamed

Try this first to check for the right files

find /tmp -user abcuser



And if you see the files are all correct and are the ones you want to delete, try this

find /tmp -user abcuser -exec...

Check this, illustrated with examples

Bash String (http://www.thegeekstuff.com/2010/07/bash-string-manipulation/)

HTH

--ahamed

You need to increase the decimal range


# awk 'BEGIN{printf("%0.10f", 100 / 2649320)}'
0.0000377455


--ahamed

Well, I am not sure why printf behaves that way, may it is not programmed to return the value but just print it out? May be it is not a function?

However, I think may be you want this?

awk...

You mean the 3rd and 4th field?
Using GNU awk


awk -F\| '
NR>1{
t1=$3; t2=$4
gsub(/[-:]/," ", t1); gsub(/[-:]/," ", t2)
if(mktime(t2) < mktime(t1))
$4=0
}1
' OFS=\|...

Try this...

awk 'p && $1 != p{print v; print}{p=$1;v=$0}' infile


--ahamed