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A modern shell will let you dereference a string with ${!...}

You must assign the string first, you can't embed the string inside the {}

STR="${MONTH}_${DAY}_${YEAR}"

echo "${!STR}"

Hi,

You can do little bit modification from balajesuri's post


#! /bin/bash

CMD=$1
ARGS=${*:2:$#}

echo $CMD
echo $ARGS


Cheers,
Ranga:)

You should've been clear with the requirements. When you say from $2 to $n, it could mean from 2nd param to 6th param out of 10 params, right?

#! /bin/bash
CMD=$1
shift
ARGS=$*
echo $ARGS

#!/bin/bash
count=0
for i in `echo $@`
do
[ "$count" != "0" ] && ARGS="$ARGS $i"
count=1
done
echo $ARGS

can you post your execution line..?
sed "0,/$searchenv/s//&\n$appendenv/" inputfile > outfile

forward slash need to be escaped..
sed '0,/<a class="string-array">/s//&\n<string>java<\/string>/' inputfile > outfile

Something to get you started. We can read the file and convert each comma to a newline.
Assming this is a Bourne-type shell.

cat filename.csv | tr ',' '\n' | while read parameter
do
...