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Or use the exit function in awk to exit immediately, e.g...

awk '/pattern/ {print; count++; if (count=2000) exit}'

Use perl...

perl -pi -e 's/pattern/replacement/g' file1

What did you try? What shell are you using? This is bash, but should also work in ksh...printf '%s%20s\n' $(date '+%Y%m%d') $(wc -l < a.dat) > a.ctl

This is a script I have to send html mail with a pdf attachment...#!/usr/bin/ksh

export MAILTO="spam@ebay.com"
export SUBJECT="Mail Subject"
export BODY="/tmp/email_body.html"
export...

You should look at the manual pages for sendmail. I have only included the bare minimum to get you started. You can add headers like "To:", "Cc:", "Bcc:", "Apparently-To:", etc. This can be done...

The Advanced Bash-Scripting Guide has some exercises (http://www.tldp.org/LDP/abs/html/exercises.html).

Try something like...$ string1='3X'

$ case $string1 in [0-9][0-9]) : ;; [0-9]?) string1=${string1:0:1} ;; esac

$ echo $string1
3

$

To execute the block, you need to have a slash / on a line of its own, after the END; line.

Try...$ cat file1
Tom|london
Tom|london
Tom|Paris
Adam|Madrid
Adam|NY
Tom|amsterdam
Tom|amsterdam
Tom|amsterdam
Tom|amsterdam

$ awk -F'|'...

You can just use sed....sed '/PATTERN/s/ to be changed/, YEHA! to be changed/' FILENAME

Try... echo $var|awk '{print int($1+0.5)}'

You could also use the shell built-in variable $SECONDS

#!/bin/sh
START=$SECONDS
:
#script commands go here
:
END=$SECONDS
echo elapsed time is $((END-START)) seconds

This will remove blank lines and those which only contain spaces...

grep -v '^ *$' $files

If you wanted to use sed, then...

sed '/^ *$/d' $files

I think that you will have to use sendmail instead of mailx to send inline html, e.g....
#!/usr/bin/ksh

export MAILTO="me@work"
export CONTENT="filename.out"
export SUBJECT="Subject"
(
echo...

In bash, variables are local to pipes.

Replacecat file | while read line
do
:
done
Withwhile read line
do
:
done < file

I thought that file ownership is just a user ID number, which you can see using ls -ln

See... https://www.unix.com/302098992-post2.html

Oh I see the problem. $1 and $2 are local to functions but you are not passing parameters to the function. Perhaps define a and b outside of the functions, e.g...$ cat sh.1
menu ()
{
echo...

The time zone "trick" is not a reliable method of performing date arithmetic.

Have a look at the FAQ:...

For datecalc, I think there are examples in the FAQ.

If you have perl, perhaps try...DATE3=$(perl -e '@f=localtime(time-(86400*7));printf "%02d%02d%02d\n",$f[5]%100,$f[4]+1,$f[3];')

Try...$ head file[12]
==> file1 <==
999
111
222
333
111
444

==> file2 <==
555
000

$ awk '/111/&&!c++{$0=$0 s};1' s="$(<file2)" file1
999
111 555
000
222
333
111

Just pipe the ls through the awk command as posted by NareshN

Try...sed -n '1p;$p' file1

This should work for any size...$ cat file1.txt
var1 var2 var3 var4 var5 var6
A G A T G T
G A A A A A
A A A A A A
G A G T A T

$ awk 'NR == 1 {
split($0, var, FS)
...

Perhaps try md5sum, e.g...md5sum -t files* | awk 'a[$1]{printf "%s and %s are the same\n",a[$1],$2;next}{a[$1]=$2}'