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sh UKBA_publish.sh UKBA Date_FINAL 3
should it not be:
sh UKBA_publish.sh UKBA $Date_FINAL 3 ?

See my comment in your post on using "urgent" in the topic, thanks.

Your first script uses ksh syntax to declare an array with set -A. In your second script you use a shebang to call bash, which...

awk splits on whitespace into fields
echo "$output" | awk '$1=="bdfo_run_date" {print $2}'To store this in a variable you can use the ` ` or $( ) (replacing the command by its output)
output=`echo...

Quick and dirty sed solution:
echo "${output}" | sed -n '/bdfo_run_date/ s///p'
Quoting ${output} preserves the formatting of the variable. sed is run in "no output" mode until it finds the string...

First: "did not work" is NOT an analysis - it is like calling the doctor and then tell him "it hurts". It might be somewhat relevant to know what "it" is...

Second: RudiC already told you that...

No awk, that's very odd. Assuming you have Kshell or bash, have a go with this. Replace the directory names with yours (I used the ones here to test).


#!/usr/bin/env bash
# change the...

cat name.txt | while read line
do
grep -e $line source.txt >> resultfile.txt
done

Output-:
msisdn | imsi | name | subscription | product | date | recharge type
09311424354 | 09488439820...

You can check this code :)


#!/bin/bash

while read MSISDN; do
awk -F'|' '/^'"$MSISDN"'/ {print $0}' source.txt >> output

done < msidsn.txt

Here's a quick and sloppy way of doing it in KSH.
{
typeset IFS='
'
while read USER_NAME
do
USER_DIR=$(grep $USER_NAME /etc/passwd | awk -F: '{print $6}') ...

This will do

FileName='specify your file here'
while read LINE
do
echo $LINE
#do your stuff here
done < $FileName

Thank you both for your help. Sorted