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Linux is the 5-megabyte file that loads when you push the power button on the computer. Everything else, everything else, is whatever software your distribution decided to bundle with this...

1. There are many linux distros for many purposes; as always your usually recommended to try em out and see which one your the most comfortable with/ is more fitting for your needs. Take BSD...

This is usually an option, yes.

You can also download images for things called livecd's, which boot a complete UNIX system from CDROM without having to install anything on your hard drive. They...

Dont know much about booting from external HD or if your computer will even allow it. You probably want to try installing/booting from a USB drive to test the OS out. There are instructions on their...

Moved thread hijack to here (https://www.unix.com/unix-dummies-questions-answers/217361-online-unix-educational-materials.html).

I should recommend that first of all you should check your all hardware like power supply, MOBO or processors issue. After it you should check your BIOS. I am confident that it's work.

Considering AMD processors have their memory controllers built into them, it could easily be the CPU.

Unfortunately, it could easily be lots of other things too; hard to be certain without...

some service/application must be responsible for the connection. try to stop the services (i would start with smbd/nmbd) one by one and check again...

Thanks, that worked fine.

Another quick question, is there an easy way to append something like "MC_" to every field on the first line?


fieldName1 fieldName2 fieldName3

MC_fieldName1...

awk 'BEGIN { FS="\t"; OFS="\t"; }; NR==1 { for(N=1; N<=NF; N++) $N="MC_" $N; }; 1' It will run the loop only for the first line. But the "; 1" should cause it to print all lines.

Usually, there is no need to run them on specific cores. Just run them simultaneously and they'll use time on whatever CPU is available and the OS deems appropriate. It will do multiprocessing...

try this...


$ awk '{if($0~/^[0-9]*$/){a+=$0;c++}if(c>=10){print a;a=c=0}if($0!~/^[0-9]*$/){if(a!=0 && c<10){print a"\n"$0;a=0}else{print}}}' input.txt
abc
def
ghi
55
36
kjld
random...

Let me know ,what desired output you want?

Try: awk '!/^[0-9]+$/&&p{print s;s=0;p=0};!/^[0-9]+$/;/^[0-9]+$/,/^[0-9]+$/{s+=$0;p=1}' file

awk '/[^0-9]/{if(s)print s; s=0; print; next} {s+=$1} END{if(s)print s}' infile

Try:
sed -n '/^0$/{N;};/^1011$/{N;};/\n/p' infile

awk 'NR%2 { L=$0; next }; L=="0" { print L; print }' datafile

How could you possibly get two zeroes printed then, when that should only cause the one on an even line to be printed?

awk 'NR%2 { L=$0; next }; (L=="0")||(L=="1011") { print L; print }' datafile

That's right...
sed -n 'N;/^0\n/p;/^1011\n/p' infile

What do you mean by 'odd lines'? One of those 0's comes from an even line(line #2).

Here ya go:

date --date=$TIME" +1 hour" +%H:%M

No matter how you cut it, getting the total space for something means scanning inodes for each and every individual file inside. No matter how you do it, the same amount of disk thrashing will...

If it's just freezing, make sure keywords.txt is in the same directory you run the command in.

$ cat module.awk

BEGIN {
# Load the list of keywords
while(getline <"keywords.txt") ARR[++C]=$1
}

# Only run this codeblock when not printing.
!P {
for(N in ARR)
...