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I added some "permission denied"... something like this?


$ cat infile
cp: writing `/testX/file2016-08-11_07-03-10AM/ext/lib/libclntshcore.so.12.1': No space left on device
cp: writing...

@fails = grep /FileNotFoundException\|I\/O exception\|fail$/, ( grep !/^\./, readdir LOGDIR );
[/QUOTE]
Actually, grep !/^\./ should not be considered as stated. grep in Perl is not similar to the...

To be honest, i can only guess, because i habitually avoid perl like the plague. It seems to me that: !/^\./ is the regular expression, where "!" means: reverse the search, give every line NOT...

It is relatively easy: the forward slash has a special meaning. Whenever you want to use a character with a special meaning literally you need to "escape" it. Escaping is done by prepending it with a...

In Perl these are the rules to create variable names:


Therefore, this is not valid in your code.
$2_zip_dirs

You can find it here in your code:
foreach my $dir ( split /\s/, $2_zip_dirs) {

I checked the bash manual page and verified that the typeset options that you listed are for bash, not ksh:

From bash manual:
typeset [-afFirtx] [-p] [name[=value] ...]
Declare variables...

Newvariable=$( echo "$Ctrcd" | tr -s '[:upper:]' '[:lower:]' )

typeset -u is supported by ksh and zsh. You seem to be using bash.
Recent bash versions (>= 4) support the following syntax:

xname1=${mname1^^}

Use Korn Shell, put below line as your shebang:
#!/bin/ksh

The difference with the earlier explanation (https://www.unix.com/302608067-post17.html) given by itkamaraj (https://www.unix.com/members/302077176.html) is !A[$4]++ . This means if the value in array...

OK in that case, try this:
awk -F\| '!/^#/ && !A[$4]++{print $4}' infile

-F\| --> Filed seperator is |

!/#/ --> process the lines which is not having #

print $4 --> print the 4th filed ( seperated by | )

sort -u --> print only unique values from the awk...

$ nawk -F\| '!/#/{print $4}' SNA_DB_UPG.list | sort -u
$PLATFORM_BIN/reload_PA_TABLE 1620_LM
$PLATFORM_BIN/reload_PA_TABLE 1626_LMT
$PLATFORM_BIN/reload_PA_TABLE 1830PSS_32...

just noticed..

please remove the highlighted single quote


awk' '{print $1}' SNA_DB_UPG.list

That's actually the syntax of if command. There must be a space surrounding [ and ]

Try giving a space between " and ] if [ -z "$build_info_table" ]

echo $1 > tmp.out
xname1=$(awk '{up=toupper($1); printf up "\n"}' tmp.out)
not tested inside of a script..

$ echo "abc" | awk '{print toupper($0)}'
ABC

echo "abc" | tr '[:lower:]' '[:upper:]'
ABC

But the best solution in my opinion is still to use the "typeset -u" way mentionned in my first post

typeset -u mname1=$1$ typeset -u name="test"
$ echo $name
TEST

You can also put it in 2 lines :

$ typeset -u name
$ name=toto
$ echo $name
TOTO

It might be worth trying to replace
sqlplus -s sna/dbmanager <<! | tee -a $LOGFILE
with
(sqlplus -s sna/dbmanager | tee -a $LOGFILE) <<!
What I am thinking might be causing the issue:
Your might...

$? is a special variable which says the previous command status.

most of the commands exit with 0 ( if it is successfully executed )

---------- Post updated at 04:47 PM ---------- Previous...

By 'documentation purposes' do you mean for a here document (http://en.wikipedia.org/wiki/Here_document)?

In theory, you can use almost any string as the delimiter, but normally you'll see 'EOF'...

If I understand you correctly. There is no multi-line documentation symbol in unix Shell (unlike some programming languages). Anything from a hash sign onwards on the same line is comment.

#The...

Not really, no.