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When you have a pipeline, the standards allow (but do not require) the elements of the pipeline to be in different shell execution environments. If your system does put them in different shell...

.* will always be greedy and match as much as possible (the whole line) but the parentheses and back-refs (in this case) force the regexp engine to back-track and give up one character of the matched...

TrY:
grep -c '\(.*\).*(\1)' infile

sed -e ':a' -e 's/\(([^)]*)\)\(.*\)\1/\1\2/;ta' infile

True.

With regard to the original post, if the script is sourced, even if the shebang is present, it is never used.

Regards,
Alister

---------- Post updated at 10:02 AM ---------- Previous...

A much less readable and maintainable version of agama's solution which is guaranteed to make whoever inherits the code mutter under their breath:

awk -F_ '!a[$1] && !a[$2] && ++a[$1] && ++a[$2]'...

n=5
insertfile=/path/to/file

{
head -n "$n"
cat "$insertfile" -
} < "$file"

That regular date with awk in post #1 will not work correctly on the first day of the month...

---
ksh93h+:
printf "%(%Y/%m/%d)T\n" yesterday

Note: That link contains some errors though, since EOF is not at the beginning of the line in the examples. And the double quotes are wrong and cannot be cut-and-pasted...

$ cat one.pl
#!/bin/perl
use Time::Local;
my $date = $ARGV[0];
$date =~ s/\s+$//;
$date =~ s/^\s*//;
my ($year, $month, $day) = unpack "A4 A2 A2", $date;
eval{
timelocal(0,0,0,$day,...

Alternatively:
awk 'getline p<f {print $1/p}' f=file1 file2

#!/bin/ksh
p="${0/.\//}"
ps -ef|awk -vp="$p" '!/awk/&&/'$p'/{print "Script is in the -> " $(NF-1)}'
sleep 1


# ./check
Script is in the -> /bin/ksh

i created a test.sh with the below contents and just executed it.


$ cat test.sh
#!/bin/ksh
echo $SHELL
echo $0
while [ 1 ]
do
sleep 5;
done


after that, i tried one more...

simply put, root gets to break the rules.

In this way we can sort


$ cat hexanumbers.txt
3E80
3EF8
460
$ cat testfile.sh
#!/bin/ksh
for i in `cat hexanumbers.txt | awk '{ print "16#"$0}'`
do
typeset -i10 i
echo $i >>...

This is a pure shell solution - should work in bash as well.


#!/usr/bin/env ksh

while read first rest
do
printf "%04d %s %s\n" ${first/-/ } "$rest"
done <data-file
exit

GNU sed:
sed 's/,,,*/\n&/2g' infile

Have you tested or benchmarked this claim?
The "grep" method essentially does a nested loop as well. It's just more concise and a more "Perlish" way of doing things.

With a setup consisting of...

# ls -li data
3180921 -rw-r--r-- 1 root root 42 Feb 4 09:33 data
# sed -i 's/2/B/' data
# ls -li data
3180920 -rw-r--r-- 1 root root 42 Feb 4 13:24 data
#


The inode changed. It's a...

Hi.

You have ^M characters in your input file?

I get normal (expected) output, then added ^M characters and got:


awk '{print $3 ";" }' FS=, file1
;000
;000
;000

$ echo qwertmyuiop | sed ':a;s/.\(.*\)./\1/;ta'
m

or
sed -e ':a' -e 's/.\(.*\)./\1/;ta'

Thanks for using indentation!

The EOF mst be at the start of the line:


#!/bin/sh

echo "\nPress 1 for automated file dumping."
echo "Press 2 for manual file dumping."
echo "\nEnter your...

instead of yy, copy the current line using y$ ( but you should be at the starting position to copy the line )..

go to the position where you want to paste, and press p to paste .. ( so it will not...

sed 's/\([^|][^|]*|\)\(.*\)/\2\1/' myFile

while read line
do
eval set -- "$line"
echo "$4"
done < infile
or:
print4()
{
echo "$4"
}

while read line
do
eval print4 "$line"
done < infile

or (ksh93/bash):
while read...