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Use double bracket, and no quotes round wild cards. The double brackets are interpreted by Bash (or Kshell if using ksh) and they both interpret the right hand side of the expression as a pattern:
...

Don't confuse the shell variable expansion substitution syntax with regular expressions because they are (just as confusing at first) and quite different.

For the full list of possibilities have...

If you have a modern Korn shell installed, ${.sh.file} should contain the name of the file that was sourced.

Have a try with something like this:

#!/usr/bin/env ksh
echo "Running test2.sh...

You are wise to use xargs as it's much more efficient. The "splat" (*) on your command line is expanding to all files in the directory. What you want is to search in your current directory:


find...

The convert utility which is a part of imagemagick will do what you need. Basic command line is:


convert +append image1.jpg image2.jpg product.jpg


The two images are placed side by side;...

I'm not familiar with the 'mtr' command, but I'll guess that its sending out pings and presenting a summary that includes packet loss. Your getting tripped up because you are parsing the whole log...

If you are using Kshell or bash, I'd suggest something like this:


ls | while read f
do
mv $f ${f#*__}
done


The ${f#*__} removes everything from the start of the filename through the...

No, it will find the whole string apply_server=1; If you need it to find just the value after the equal, use this:


split( substr( $0, RSTART, RLENGTH ), a, "="); # split the token at the =...

Sorry, misinterpreted your need. Maybe this sample will give you what you need:


awk '
{
if( match( $0, "apply_server=.*[ \t]" ) ) # search the input line for the...

Using the syntax $(i) will allow you to access a column using the contents of a variable, in this case 'i'.


#!/usr/bin/env ksh
awk -v col=${1:-1} ' {print $(col)}'


This example accepts a...

Have a go with this:


#!/usr/bin/env ksh

awk -v date=${1:-nodate} '
/BEGIN:VEVENT/ { cache = 1; }

/LAST-MODIFIED:/ {
if( index( $0, date ) )
drop = 1;
...

Have you tried reading the data into an array which would allow you to avoid the substring overhead which I believe is costing you. Your original code ran in about 4 seconds for me using Bash and...

ERK!!

I made a change, and tested it, but failed to see all zeros. Going blind I think.

I've fixed the bug by reverting to my original logic and it works now for me. THANKS!


awk '
...

Assuming your data is in a file named t.data this is one way:


awk '
/>/ { split( $1, a, ">" ); sect=a[1]; next; }

/Start/ {
s = "";
printf( "%s ", sect );

...

Ah, very good, thanks.

Have a go with this:

awk '
/property name=/ {
gsub( ".*value=" Q, "" );
gsub( Q ".*", "" );
print;
}
' Q="'" RS="[<>]"

...

First of all, you don't need to cat into a while, you can redirect the file into the while:


while read stuff
do
echo $stuff
done <$ELOG


Further, the use of awk isn't needed either....

Have a go with these small changes:


if ! lpar-command | awk '
/^Name/ { next; }
/^---/ { next; }
{
state[$2] = state[$2] $1 " ";
if( $2 == "A" )
acount++;
else
...

Assuming your system will allow 100 concurrent file descriptors to be open at the same time:


awk '
{
for( i = 3; i <= NF; i++ )
printf( "%s %s %s\n", $1, $2, $(i) ) >i...

Not quite the way to get date in. From inside of awk you cannot use backquotes like that. This is one way which should work with even older awks. I haven't used an AIX system since about 2001, and...

Small changes to generate the total counts:


awk '
/^Name/ { next; }
/^---/ { next; }
{
state[$2] = state[$2] $1 " ";
if( $2 == "A" )
acount++;
else
others++;...

Agree with spacebar -- can be simplified. My thoughts:


lswpar | awk '
/^Name/ { next; }
/^---/ { next; }
{ state[$2] = state[$2] $1 " "; }
END {
printf( "====...

Child is writing result on p3, but parent is reading, the already closed, p2.

Use the man command to look at how to use the mesg command. man mesg

This should give you the information that you need to solve your problem/answer your question.

If your input file is sorted such that the records with the same first field are always together, then this should work:


awk -F \| '
$1 != last {
if( hold )
print...

This should work if you are using Kshell or bash:


awk ' {do-something}' "$@" >output-file


If you have more than the two file names on the command line, then:


awk '{do-something}' $1 $2...