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Hi, try double quotes:
sed "s/${TOKEN1}\(.*\)${TOKEN2}.*/\1/" "$INPUT1"
The curly braces for variable expansions are good practice within strings, for reasons of readability and also to prevent...

Hello jcdole,

Yes, that could be shorten to following.

MY_PATTERN="="
SOME_VAR=$(awk -F"$MY_PATTERN" '{split($1,array," ");print array[3]}' Input_file)
echo "$SOME_VAR"


Thanks,
R. Singh

Using built-in parameter substitution (https://www.ibm.com/support/knowledgecenter/en/ssw_aix_72/osmanagement/korn_shell_parmsub1.html):-

while read line
do
SOME_VAR="${line%%=*}"
...

This might work:
awk "/zypper_local/ && /60/ && /${ZYPPER_LOCAL_REP//\//\\/}/" file; or try (given the order of the substring is as given):

grep "zypper_local.*60.*$ZYPPER_LOCAL_REP" file

...

Give a try replacing your :



awk '/zypper_local/ && /60/ && /$ZYPPER_LOCAL_REP/'with :

awk -vP="$ZYPPER_LOCAL_REP" '/zypper_local/ && /60/ &&($0~P)'


You can also try to get out the...

Here I used awk to replace everything except "#" on your "§" line with spaces. This is used as a template to insert the required comments:
awk -v D=2019_08_25 -v V=34-1-9 -v M=9-7-3 '
function...

Try:
find path \( \
\( [condition A] \) -prune -o \
\( [condition B] \) -prune -o \
\( [condition C] \) -prune \
\) -o -print


Example:

$ mkdir -p...

It is a "bracket expression" at begin-of-line ("^", as you used it in your substitution). man regex:

You escaped one address delimiter too many. man sed:


Try your sed command again, with the second | unescaped.


To avoid commenting out an already commented line, you can either add the # ...

It's okay.
If all of you directories start with $A_START_PATH
then you can perhaps cd to it and use shorter names (relative to the current directory).
cd "$A_START_PATH" || exit
A_LIST="dir1 dir4...

No, it is because .* matches .. and .
Test the glob expansion with echo!
This is for the arguments = start files.
If one of the start files is a directory, chown -R will recurse into it and find...

Hi.

Does this demonstration help?
#!/usr/bin/env bash

# @(#) s1 Demonstrate calling function from find -exec.

# Utility functions: print-as-echo, print-line-with-visual-space, debug....

rsync has no concept of hidden files and processes both files identically for me.

See my testing transcript below where both files copied OK:

$...

Hi,
You are this problem because when used in a function, the built-in declare makes local variable. The -g option suppresses this behavior.

A solution could be:
declare -p ARRAY_MAIN_REPO_LEAP...

-o is OR within [ ] (and in test arguments)
|| is OR in the shell
So it is either
if [ $x -gt 0 -o $y -gt 0 ] ; thenor
if [ $x -gt 0 ] || [ $y -gt 0 ] ; then

Hello jcdole,

Could you please try following and let me know if this helps you.

VAR1=$(grep -oE '.*ext4[[:space:]]+' Input_file)
VAR2=$(grep -oE 'acl.*[[:space:]]+' Input_file)
Now be very...

Without quotes, the words in the expansion of $MY_TOKEN are passed to echo as separate arguments by the shell. The echo utility then prints each of its arguments separated by a <space> character and...

MY_TOKEN is not define anywhere, so any output is somewhat surprising...
The first two outputs are identical, and should be - the curly braces are meant to protect a variable name and should not...

This solution has evolved over the weekend but as there have been no further replies I'll update in-place.

My final solution avoids changes of $IFS and the set -f builtin. Firstly an example of...

Would this help?echo "ABCDEF+1234" | grep -E "[\x26-\x40]"
grep: Invalid range end
echo "ABCDEF+1234" | LC_ALL=C grep -E "[\x26-\x40]"
ABCDEF+1234

---------- Post updated at 17:49 ----------...

You could use echo $L_TEMP | grep -v "[^[:print:]]"
or, with a recent shell, L_TEMP_TEST=${L_TEMP//[[:print:]]}The second would leave L_TEMP_TEST empty if no non-printable chars are in the variable,...

Try L_TEMP=$a$'\x07'$b
or L_TEMP=$a$'\a'$b

How about while read PROJ; do PROJ=${PROJ##*/}; echo $PROJ; done < $MY_TEMP_RESULT_1 | sort | uniq -d
another_project
dir_1-3-2-1-1
some_project

You need to specify the character(-set) that is before the beginning of the string.
If there is nothing before - the string is at the beginning of the line - then give ^.
sed...

Hi,
A possible syntax, but line mustn't begin with the string to search (not tested):
sed 's/\([[:space:]]\)string1\.string2\.string3@/\1new_string1.new_string2.new_string3@/g'
Regards.