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Try also
sed 's/<?=test.getObjectName("[^"]*",//; s/, *"D") *?>//; s/[" ]//g; s/\([^,]*\),\([^,]*\)/\2.\1/ ' file
testTBL
testDB.testTBL

sed 's/--[^\r]*\r//g' file

Andrew

Try this

$ awk '{for(i=2;i<=NF;i++){split($i,A,"-");for(j=A[1];j<=c=(A[2]>A[1])?A[2]:A[1];j++)printf $1"~"j OFS}printf RS}' file HELLO~100 HELLO~101 HELLO~102 HELLO~103 HELLO~104 HELLO~105...

Please use code tag

Try

$ cat file
100-105
107
108-112

$ awk -F'[-]' '{for(i=$1;i<=c=(NF==1)?$1:$2;i++) printf i OFS ;printf RS}' file

100 101 102 103 104 105
107
108 109 110 111...

Providing you have the GNU version of the date command available this should work.


#!/bin/bash
#
#

# check the command line
if [ $# -ne 1 ]
then
echo "Usage: ${0##*/} <year and day...

awk -F"HELLO_" '{print $2}' filename | awk -F"_BYE" '{print $1}'

Try: perl -F";" -ane 'print if $F[1]=~/HELLO_UNIX_[^_]+$/' file

another one

awk '/Hello/{getline x;sub("Name","IDENTITY",x);print $0 RS x;next}1' infileawk '/Hello/{print;getline;sub("Name","IDENTITY");print;next}1' infileThat last one also works if the first...

Assuming your file has real double quotes instead of the so-called smart quotes:
awk -F "\"" ' {
for(i=1;i<=NF;i+=2) {
gsub(";", "|", $i)
}
}1' OFS="\"" file

ls [0-9]*abc[0-9]*

or

ls *abc* | grep -v "*.gz"

They are generally interchangable, however the curly braces disambiguate the variable, so for example:

var="to the "
echo "Hello$varworld"
echo "Hello${var}world"

Would return two different...

${var} is usefull when you want to include the variable in some echo output (in shell, in perl it can be print), that needs to be followed immediately by some string. Here is an example:
This wont...

In principle they are the same, but one should use ${var} if $var is immediately followed by an alphanumerical character or an underscore (_) . The curly brackets are also necessary if you want to...