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Can you post what you've tried to solve this...and what about records that are less than the current date

Good catch...so here's the updated awk recipe:
awk '{if($NF==0 || $NF+0) print $NF}' file

What do you mean by an empty file...a file with size zero bytes or one that is filled with zeros?

No need for the while loop...first remove everything that follows the comma on each line of the pattern file with awk and pipe its output to grep...
awk -F, '{print $1}' pattern_file | xargs grep {}...

Hopefully this sed one liner might work...
sed -e 's/\([0-9]\)\([A-Z]\)/\1 \2/g;s/\([a-z]\)\([A-Z]\)/\1 \2/g;s/\([A-Z]\)\([A-Z]\)\([a-z]\)/\1 \2\3/g;s/^\([0-9]*\) //' file

I get the desired output by tweaking the FS in your "first awk"...
awk -F"\"[,:]* *\"*" '{
for (i=1; i<NF; i++) {
if ($i ~ "path") print $(i+1)
else if ($i ~ "Sample Name")...

Then why dont you post a sample of the exact input that is to be worked on...please dont expect us to read your mind :confused:

So what is to be done with those lines that have neither intronic or exonic in them?

You can convert decimal to binary using bc...there is no need to write a special C program...
echo "obase=2;1234" | bc

Post a sample of the input and desired output...because imo this can all be done with a single nawk without the need for a pipe...

Yet another way of doing the same thing with awk..
awk -F\| '{OFS="|";gsub(",",RS$1FS,$2);print}' file

Yet another way of doing the same thing with awk...
awk -F"[ ]" '{for(i=1;i<=NF && ($i=="");i++);print "there are "i-1" spaces leading upto " $i}' file

@OP: we are at a point where it is pointless to proceed unless you post the contents of the makefile...your env is setup properly but there is something in your makefile that is erroneous so unless...

If you have perl already then it should be pretty simple to solve this problem...

Any reason to insist on grep instead of sed or awk for parsing your input...
sed 's/\(.*>\)\(.*\)\(<.*\)/\2/g' file
or
awk -F"[<>]" '{print $3}' file

Can you post what the desired output should look like...

This should work albeit untested... awk '{for(i=1;i<=NF;i++) if($i ~ "^(IN|OUT)$") print $3,$i,$(i+1)}' file

Give this perl script a try...

#!/usr/bin/perl

use Time::Local;

while (<>) {
@f = split /\|/, $_;

($y1, $o1, $d1) = (substr($f[3], 0, 4), substr($f[3], 5, 2), substr($f[3], 8,...

Change the echo to print...

Store all hostnames in a file ("servers" for example)...

cat servers
aaaa
cccc
dddd

Run the awk script on "InputFile.txt" to get the desired output separated by criteria into different...

That was specific to your question as you were looking for 4 patterns and if you want something generic then take out the n...

---------- Post updated at 12:59 PM ---------- Previous update was at...

Well you could give this [g]awk a try...

gawk '{
for (i=1; i<=NF; i++)
if ($i ~ "^(error|fail|panic|accepted)$")
a[$i]++
} END {
for (i in a) {
n++
...

Not sure what you're looking for...can you be more clear about your requirements...

That's because uniq expects its input to be sorted...so that duplicate lines are adjacent to each other...in fact uniq can be eliminated by using the "-u" option to sort...
sort -u test.txt | grep...

That is correct...you cant embed variables in a /regexp/...