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No. But would not hurt.

No. But would not hurt.

Yes. Very different.

I recently joined. I just found it by googling.

I think the forum is very good. I've enjoyed it, both for learning new things from some really smart people, and trying to contribute my knowledge....

$ sed -n -e "s/Date and Time: \(.*\) MST/\1/p" -e "s/Number of Records: *//p" input
2013-05-11 12:23:12
000005

That's for sending the exact input file and script you are using. That really helped.

I took another look, tried several things, learned it's a sticky wicket, found something that seems to work...

That is correct. Thanks. As I said before, I did expect adding the extra \ would work, was surprised it did not. I just copied the posted script verbatim, did not see the extra semicolon. Here is the...

You set the environment variable in $HOME/.profile or $HOME/.bash_profile or other shell configuration file that your shell is using. Using bash shell, you would add a line saying:
export...

I read it as "n == 3". But you're right, it's not really clear.

If the intent is "n >= 3", then you either:
- Use the scrutinizer shorter solution designed for "n >= 3", or
- Change == 3 to >=...

Here is a way to do it using awk.
$ awk '{cnts[$1]++} $2 > fld2[$1] {fld2[$1]=$2; fld0[$1]=$0} END {for (key in cnts) { if (cnts[key] == 3) print fld0[key] }}' input3
A 5
B 5
C 10

Here's how to do it in general:
$ cat test.awk
BEGIN { FS=OFS="," }
{n=0; for (i=1;i<=NF;i++) {($i ~ /(*)/) && n++}}
{ print "Fields: " NF, " Matches: " n}
n == 0 {$NF="OFFLINE"}
n < NF-3...

You pass variables from a.sh to b.sh by adding the variable after the script name, such as b.sh "$x". You receive variables in b.sh by using $1 for the first variable passed, $2 for the second, etc....

$ cat input
hiring,no
system,yes
hiring,yes
quota,no
quota,maybe

$ sort input | awk 'NR == 1 {p=$1; next} p == $1 { print $1 " is duplicated"} {p=$1}' FS=","
hiring is duplicated
quota is...

Here is the input you most recently posted:
$ cat input
2 9647701612350 9647701168456 262 23 1303031257462B0300 1303031259182B0300 92 9647701146402 0
5 ...

awk 'NR>1 && !/^\+/{print RS}1 END{print RS}' ORS= file1
Should be (using gawk anyway, did not test with other awk versions):
awk 'NR>1 && !/^\+/{print RS}{print} END{print RS}' ORS= file1

$ cat...

I'm not sure what the hadoop command is doing. Anyway, maybe this might work:

SOURCE=/path/to/files/
find "$SOURCE" -type f -mtime -1 -exec cp -v "{}" /usr/path/ \;

Here is one possible way:
ls | grep -v dasd_91197.trc | xargs rm
If more than one file to retain:
ls | grep -v -e dasd_91197.trc -e someother.trc | xargs rm

---------- Post updated at 04:49 AM...

Here's how I would put it. Much of this you probably already know.

If you declare int n = 4;, then the compiler reserves a special location to store an int value, and stores 4 there. No big deal....

Because arr[0] is exactly the same as *arr

In general, arr[i] is exactly the same as *(arr + 1)

This is one of the most difficult and fundamental concepts of C programming. It took me years of...

Suppose you had "int int_array [12]". Then "int_array [n]" would be an int.

argv is declared as "char *argv []" So "argv [n]" is a "char *".

"char *" is what "printf %s" expects and what makes...

There are widely used ways to automatically and securely log into remote systems using public and private keys that are stored in files. It's been a while, so I don't remember the details, but I used...

In that case, I would try using rsync to transfer the files.

Or, you could create a tar file with files / dirs starting with a-m, transfer it, delete it, then make another for those starting with...

$ sed ":a s/^\(.\{120,125\}\) /\10/; T; ba" input
A 4175.0 8055.01211 75 1 -2172671 77 45 16 457626.4 2609265.1 131.3 1090 102 1 1T N/A124000015 0.8 ...

If you want to reverse a string, here is the best way:
$ echo welcome | rev
emoclew

There is no hard and fast rule. But from my experience:

Learn head and tail first, and use them preferably. They are simple and well suited to specific task. uniq, grep and tr are also quite...

I think some of your expected output is incorrect. Anyway, try the following.


$ cat test.awk
NR==1 {split ($0, headers); print; next}
{
x=NF; $11=$12="-"
for (i=2; i<x; i++) {
if ($i > 5...

echo `expr substr $x 1 expr ${#x} - 1`

At least one reason your nested substitution does not work is because you only have one set of `` backticks. Regardless of whether you use the older backtick...