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How would i delete a line at specific line number

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# 1  
Old 06-15-2010
How would i delete a line at specific line number
Hi guys ,

I m writing a script to delete a line at particular location.

But i m unable to use variable for specifying line number.
for example.
Code:
sed -n '7!p' filename

works fine and deletes 7th line from my file
but
Code:
sed -n '$variable!p' filename

gives following error.

Code:
sed: -e expression #1, char 3: extra characters after command

# 2  
Old 06-15-2010
use double quotes instead when using shell variables.
This User Gave Thanks to clx For This Post:
pinga123
# 3  
Old 06-15-2010
Quote:
Originally Posted by anchal_khare
use double quotes instead when using shell variables.
+
i tried
Code:
sed -n "$variable!p" vm.cfg

and

Code:
sed -n '"$variable"!p' vm.cfg

None of them are working.
Please help.
# 4  
Old 06-15-2010
Code:
[house@leonov] cat in.file
1st line
2nd line
3rd line
[house@leonov] var=2; sed "${var}d" in.file
1st line
3rd line

This User Gave Thanks to dr.house For This Post:
pinga123
# 5  
Old 06-15-2010
Another way:
Code:
sed ''${variable}'d' vm.cfg
    ^^
This is two single quotes, not a double!

This User Gave Thanks to zaxxon For This Post:
pinga123
# 6  
Old 06-15-2010
You don't really need quotes at all.

Code:
$ cat file1
a
b
c
d

$ X=3
$ sed ${X}d file1
a
b
d

This User Gave Thanks to Scott For This Post:
pinga123
# 7  
Old 06-15-2010
Thanks for your input . But now i would like to enter a line at specific line number .

How would i establish this using sed.
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