Shell Programming and Scripting

I am wondering if there is a way via grep and sed to extract a string that is on the 2nd line below a known marker as in this example:

TextRel 203 0 0 "WELL:"
SetPosAbs 1287 -6676
TextRel 210 0 0 "AEP #2"

The marker is WELL:, but the string I need is "AEP #2". Can grep/sed handle this or is some sort of read command required?

Thanks,

Paul H.
Denver

Code:

nawk -v qq='"' 'c&&!--c {print substr($0, index($0,qq))};$NF ~ "WELL:" {c=2;next}' myFile

I used your code in the following string:

Set Well = `nawk -v qq='"' 'c&&!--c {print substr($0, index($0,qq))};$NF ~ "WELL:" {c=2;next}' $file`
echo $Well

I got the following message:

1: Event not found

Perhaps I should have added that I am using Cshell and that the 3 data lines shown in my original post are part of a larger file. The string "WELL:" however is the first instance of that string in the file. Hope that doesn't make it more difficult.

Thanks,
Paul H.

it should have worked regardless of the shell, but csh might be a different story.
Try executing from the command line and see what it gives you.

Using the following command at the command line prompt:

nawk -v qq='"' 'c&&!--c {print substr($0, index($0,qq))};$NF ~ "WELL:" {c=2;next}' asciipds

I got the following message:

123: Event not found

I know that the file asciipds is present and that it does contain the string "WELL:" as shown in my original post. Perhaps it is the csh after all.

Thanks,
Paul H.

Another way:

Code:

awk '/"WELL:"/{getline;getline;print $5, $6; exit}' asciipds

Regards

That works both at the prompt and from within the script. Thanks Loads,

Paul H.