Shell Programming and Scripting

I've been searching around here and other places, but can't put this together...

I've got a unique list of words in file 1 (one word on each line).
I need to delete each line in file2 that begins with the word in file1.

I started this way, but want to know how to use file1 words instead of supplying a keyword:

sed -e '????/d' < file2 > file3

sed -e '`cat file1`/d' 012703.csv 061603.csv

I want to put something at the ???? that reads each line of file1. Any help would be greatly appreciated!

LSM

while read WORD
do
sed '/'$WORD'/d' file2
done < file1

Thanks! I want to put the new file2 (with the lines already deleted) into a new file3. Also, I need to make sure $WORD is at the beginning of the line. I tried the below but got an empty file3.

while read WORD
do
sed '/$WORD/d' file2 > file3
done < file1

Any suggestions?

Use a for loop?

Code:

for Word in `ls <unique list of words filename>`
do

 sed -e '$Word/d' < file2 > file3

done

See if this works:

Code:

cp file2 file3
while read WORD
do
  sed '/'$WORD'/d' < file3 > TMP_00
  mv TMP_00 file3
done < file1

or this, which may be faster:

Code:

while read WORD
do
  cmd="$cmd -e /$WORD/d"
done < file1

`sed $cmd < file2 > file3`

That works! Now I want to make sure that $WORD is at the beginning of the line. Shouldn't this work?

while read WORD
do
cmd="$cmd -e /^$WORD/d"
done < file1

`sed $cmd < file2 > file3`

THIS IS file1 CONTENTS:

15
16
17

THIS IS file2 CONTENTS:

15
16
What is the meaning of 17
18

I WANT file3 TO BE WRITTEN AS:

What is the meaning of 17
18

That is... lines 1 and 2 were deleted because they began with 15 and 16... Right now I'm getting file3 that looks like this:

18

Thanks for any help!

I can't duplicate your failure. I get the two lines that you want. What shell are you using? Can you try it with ksh or bash?

And you don't need those backquotes around the sed command. Try getting rid of those.