Getting file names


 
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# 1  
Old 04-28-2011
Getting file names

THE END

Last edited by kristinu; 04-28-2011 at 03:13 PM..
# 2  
Old 04-28-2011
Try :
Code:
set myLst=$(echo $Lst | sed "s/-run.*.log//g")

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!

Last edited by vgersh99; 04-28-2011 at 12:31 PM.. Reason: code tags, please!
# 3  
Old 04-28-2011
Code:
set AfullNameLst = "n01-run1.log n01-run2.log n01-run3.log n02-run1.log n02-run2.log"
set fnameLst = `echo $AfullNameLst | sed "s/-run.*.log//g"`
echo $fnameLst

But am getting

Code:
fnameLst = n01

instead of

Code:
fnameLst = n01 n02

# 4  
Old 04-28-2011
Code:
echo 'n01-run1.log n01-run2.log n01-run3.log n02-run1.log n02-run2.log' | sed 's/-run[^ ]*//g'

# 5  
Old 04-28-2011
That's better, but now am getting

Code:
fnameLst = n01 n01 n01 n02 n02

rather than the names irrespective of run numbers.
# 6  
Old 04-28-2011
Code:
echo 'n01-run1.log n01-run2.log n01-run3.log n02-run1.log n02-run2.log' | sed 's/-run[^ ]*//g' | tr ' ' '\n' | sort -u | tr '\n' ' '

# 7  
Old 04-28-2011
THE END

Last edited by kristinu; 04-28-2011 at 03:14 PM..
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