UNIX for Dummies Questions & Answers

Hello all. Hope you can help. I am looking for a complete command to search for a file named HOSPCHK. The file could be listed with numbers after it like [0-9] it could be listed with letters after it [a-z] or a combination of both or just by it self. The other catch is the file that I want to look for has no extention on it. So I have been playing with the following:

Code:

ls -l *\*\*\HOSPCHK*[0-9] | awk '{ print $5 }
ls -l *\*\*\HOSPCH*[a-z]*[0-9] | awk '{ print $5 }
ls -l *\*\*\HOSPCHK | awk '{ print $5 }

Can you suggest anything that would capture that file a better way?

Thanks for any help with this.

Does the file exist in filename versions that you do not want to find?
Why not a simple wildcard * to find anything?

When I do the wildcard it picks up the files with the extensions. I was looking at things like '/\./' but I am a true newbee and couldn't get that to work...also playing with the grep but no luck.

Code:

ls -1 sample* | awk -F. '{if ($2<="") print $1}'

in place of sample, you could substitute your search string - HOSPCHK

I tried ls -1 HOSPCHK* | awk -F. '{if ($2<="") print $1}' and it didn't seem to find it...also tried ls -1 *\*\*\HOSPCHK* | awk -F. '{if ($2<="") print $1}'. Checked the directory to make sure the file was in there and it does exist. Can you see anything wrong with those statements?

Just do the first half of the ls -1 without the awk argument.
See if you get filenames listing.

Yep when I do the ls-1 *\*\*\HOS* I get about 6 files. It includes the file I want but also includes 5 files with extentions on it.