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How to get a timestamp when running nohup & from a shell?

 
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# 1  
Old 06-11-2014
How to get a timestamp when running nohup & from a shell?
Hi,

I am running nohup cp & in a shell script.

How do I get a timestamp so I can get a timing of how long the copy took?

Roughly, the script does something like below:

Code:
date
nohup cp -rp /files/source /files/target &
date

I am mainly wanting to know how long it took for the copy to finish. The directory/ies that I am copying is between 10-100GB.

Please advice. Thanks
# 2  
Old 06-11-2014
One way is to redirect output to a file and then check the time of the file after the command has completed.

Code:
date
nohup cp -rp /files/source /files/target > results_of_copy.log 2>&1 &

# 3  
Old 06-11-2014
try
Code:
nohup time cp -rp /files/source /files/target > test.log &

# 4  
Old 06-11-2014
Putting a command in the background means that you lose the flow. Your initial:-
Code:
date
nohup cp -rp /files/source /files/target &
date

.... will just give you two timestamps almost immediately sequentially and your script will continue whilst the copy make still be progressing.

What are you actually after? If you keep the copy in the foreground of your script (take off the nohup and the &) then you will get the correct before & after times.

For a marker telling you the elapse (and other info) just use this:-
Code:
date
time cp -rp /files/source /files/target
date


I hope that this helps



Robin
# 5  
Old 06-11-2014
Have you tried using rsync instead of cp? I usually do "rsync -av"
which will tell you how log the file took to copy.

Code:
$ rsync -av /etc/oratab .
building file list ... done
oratab

sent 858 bytes  received 42 bytes  1800.00 bytes/sec
total size is 736  speedup is 0.82

You can add --stats to get even more information,
plus you can add compression with --compress if you want

Code:
$ rsync -av --stats --compress /etc/oratab .
building file list ... done

Number of files: 1
Number of files transferred: 0
Total file size: 736 bytes
Total transferred file size: 0 bytes
Literal data: 0 bytes
Matched data: 0 bytes
File list size: 60
File list generation time: 0.001 seconds
File list transfer time: 0.000 seconds
Total bytes sent: 76
Total bytes received: 20

sent 76 bytes  received 20 bytes  192.00 bytes/sec
total size is 736  speedup is 7.67

# 6  
Old 06-11-2014
You could also try:
Code:
nohup sh -c 'date;cp -rp /files/source /files/target;date' 2>&1 > cplog &

This User Gave Thanks to Don Cragun For This Post:
mjf
# 7  
Old 06-11-2014
Quote:
Originally Posted by rbatte1
Putting a command in the background means that you lose the flow. Your initial:-
Code:
date
nohup cp -rp /files/source /files/target &
date

.... will just give you two timestamps almost immediately sequentially and your script will continue whilst the copy make still be progressing.

What are you actually after? If you keep the copy in the foreground of your script (take off the nohup and the &) then you will get the correct before & after times.

For a marker telling you the elapse (and other info) just use this:-
Code:
date
time cp -rp /files/source /files/target
date

I hope that this helps



Robin
Hi,

I want to be able to use several nohup & in the shell script so as not having to wait for the one cp to complete to proceed with the next cp.

But as you pointed I can take out the nohup and run nohup the shell itself and I will get the timestamp.

Just want to make sure I understand what you mean by not using nohup &. If let's say I have several scripts name x1.sh, x2.sh that contains line like below:

Code:
#!//bin/ksh
x1.sh
date
cp -rp /app/source/dir1 /app/target/dir1
date

#!//bin/ksh
x2.sh
date
cp -rp /app/source/dir2 /app/target/dir2
date

Then I should be able to run each of them as below and get the date output, is that correct?

Code:
nohup x1.sh & 1>x1.out 2>&1
nohup x2.sh & 1>x1.out 2>&1

Thanks in advance.
 
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