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Need help in printf in shell script

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# 1  
Old 04-17-2013
Need help in printf in shell script
My requirement is need to add spaces to the string with the dynamic value to printf... this is a part of shell script ..which i have , the length is not static ...

Code:
length=15
value="1234567890"
 printf "%-"$length"s\n" "$value";

The result it is printing is ... i am not sure y it is printing %-15s..

Code:
%-15s
 1234567890

# 2  
Old 04-17-2013
You can do it like this:

Code:
 printf "%15s\n"  "$value"


For dynamic:
Code:
printf "%*s\n" $length "$value"

Guru.
This User Gave Thanks to guruprasadpr For This Post:
greenworld123
# 3  
Old 04-17-2013
it is printing like below
Code:
*s
*s

# 4  
Old 04-17-2013
printf
Hey!!!


Another way is,

Code:
pat='%'${length}'s\n'
printf $pat "$value"

Cheers,
Ranga Smilie
# 5  
Old 04-17-2013
Code:
$ echo $SHELL
/bin/bash

Code:
$ cat temp.sh
length=15
value="1234567890"
printf "%*s\n" $length "$value"

Code:
$ ./temp.sh
     1234567890

# 6  
Old 04-17-2013
Quote:
Originally Posted by guruprasadpr
You can do it like this:

Code:
 printf "%15s\n"  "$value"


For dynamic:
Code:
printf "%*s\n" $length "$value"

Guru.
This is working fine ... how can i do samething .. to append zero's instead of spaces ..
# 7  
Old 04-17-2013
Code:
$ cat temp.sh
length=15
value="1234567890"
printf "%0*d\n" $length "$value"

$ ./temp.sh
000001234567890

This User Gave Thanks to hanson44 For This Post:
greenworld123
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