Shell Programming and Scripting

Im trying to execute application and its return code is below

IF Status code=o
echo "........"

else Staus Code =-2 DJRE

then echo "......"

Can any one help me how to handle the status code and echo some message.

I guess you call your function like this:

result=`Your_function`

# From your question it is a character 'o', if so then use the below condition
if [ "$result" = "o" ]
Just in case you meant the number 0 (zero) then use the below condition
if [ $result -eq 0 ]
then
echo "....."
else
echo "....."
fi

BTW, can you tell me how to post a new question in this forum. I appear too dumb as I spent already 15 mins finding the place for submitting questions.

Nanu_Manju: when you enter a forum, like Shell Programming and Scripting - The UNIX Forums, there's a "New Thread" button above the list of "Threads in Forum", and one below the list too.

Thanks, I hate when I appear dumb. You have a good day

ls -lrt *20080430 | grep -v | wc -l

ls: 0653-341 The file *20080430 does not exist.
0

We need to skip File does not exist like like total using grep command

can any one help how to acheive this

The output will be zero lines if there are no files, so wouldn't it suffice just to discard the error message?

Code:

ls -lrt *20080430 2>/dev/null | wc -l

PS. Please start a new thread for a new question.

HI,

Returncode = `cd $Path;ls -lrt *$fdate 2>/dev/null | wc -l`
if [ "$Returncode" = 0 ]
then
echo '.......'
else

cd $Path;ls -lrt *$fdate 2>/dev/null

but it showing the error Returncode not found
help me please